1. Six dogs, each having a mass of 32 kg, pull a 325 kg sled horizontally across ice. If each dog applies a force of 86 N [fwd], what average acceleration es the sled experience? Assume that friction is negligible. Equation: F=ma My solution: 6 x 86 N= 516 N F=ma a= F/m a= 516 N [fwd]/ 325 kg a= 1.588 m/s2 a= 1.6 m/s2 I just have a problem understanding the question. Help please!