Help Total mechanical energy question

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SUMMARY

The discussion centers on calculating the speed of a 1 kg rock thrown upwards at 20 m/s from a height of 30 m, using the principle of conservation of total mechanical energy. The total mechanical energy (Etotal) is defined as the sum of gravitational potential energy (Egravitational) and kinetic energy (Ekinetic). At the moment just before the rock hits the ground, its gravitational potential energy is zero, and the total mechanical energy remains constant, allowing for the calculation of its speed using the equation Etotal = Egravitational + Ekinetic.

PREREQUISITES
  • Understanding of total mechanical energy conservation
  • Familiarity with gravitational potential energy (Egravitational)
  • Knowledge of kinetic energy (Ekinetic) calculations
  • Basic principles of projectile motion
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  • Study the conservation of energy in mechanical systems
  • Learn how to apply the kinetic energy formula: Ek = ½mv²
  • Explore gravitational potential energy calculations: Eg = mgh
  • Investigate projectile motion and its equations
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Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of energy conservation in motion.

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[SOLVED] Help! Total mechanical energy question:)

Q. Suppose you are standing on a 30 m building and throw a 1 kg rock upwards at 20 m/s. Knowing that total mechanical energy is conserved, calculate the speed of the rock when it hits the ground.


Total Mechanical Energy equation:

Etotal = Egravitational + Ekinetic
Et = Eg + Ek
= mgh + ½mv2


What is the speed of the rock when it hits the ground? Well, the gravitational potential energy would be 0, if the reference point is the ground, yes? The upwards motion of the rock has thrown me off:confused:
 
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Correct me if I'm wrong, but when the rock hits the ground, wouldn't the speed be zero? It's not moving.
 
adv said:
Correct me if I'm wrong, but when the rock hits the ground, wouldn't the speed be zero? It's not moving.
The problem is asking you to determine the rock's speed at the instant just before it hits the ground.
Since total mechanical energy is conserved, the mechanical energy that the rock has at the instant it leaves the thrower's hand must be equal to its total mechanical energy at the instant just before it hits the ground.
 

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