Recent content by Air

When I substitute into each other, they all just cancel out to 0=0.

The whole question is posted in post number 3. https://www.physicsforums.com/showpost.php?p=4410136&postcount=3

I understand how the equations are set up but I can't seem to solve the maths to get the equilibrium constants. Is there something I am missing? Like I said, I am aware that X = 200 thus that value remains at that. Also, From the fourth equation K_{out} = Cl_{out}.

From this, finding the concentrations at equilibrium.

Homework Statement With the 5 equations, the equilibrium contants can be calculated at the bottom. (See image) My complication I am aware that X = 200 thus that value remains at that. Also, From the fourth equation K_{out} = Cl_{out}. But, I cannot seem to work out the values. If not...

Oh yes, that is correct. Silly mistake. Thanks.

This is a question... For the following question: y^{'}=\frac{dy}{dx}=3y I get the solution... \int \frac{1}{3y} dy = \int dx \frac{1}{3}ln y = x + c y = e^{3x}+e^{3c} However the textbook example says the solution is... y = ce^{3x} My question is would my answer be incorrect...

Merry Christmas everyone! :smile:

Homework Statement Find the maximum shear stress for \sigma _{xx} = 120 MN/m^2, \sigma _{yy} = 50 MN/m^2, \tau _{xy} = 40 MN/m^2Homework Equations \sigma _{min} = 0.5(\sigma _{xx}+\sigma _{yy})-0.5((\sigma _{xx}-\sigma _{yy})^2+4\tau _{xy} ^2 )^{0.5} = 31.8 \sigma _{max} = 0.5(\sigma...

I live in UK. I haven't seen the ash but it's said that it's so high up that it doesn't effect people living here and thus it is not visible. As for people stuck abroad, trains are very booked. Also, in France, there are train strikes which makes the situation harder...

Also, what is that dot they have in the bar mean? At point A.

Oh yes. It's -(1.8)(0.5). Found 1.8 in the step earlier and forgot to put that in. Thanks.

Homework Statement To find the reaction at A and B. (See image below) Homework Equations Moments and Area The Attempt at a Solution Area of load: (0.3)(6) = 1.8kN Moments about A: -(6)(0.15) + RB(0.6) = 0 --> RB = 1.5kN 4. The error and question I get the reaction force at...

Just popped by to wish everyone here on PF a merry christmas. :smile:

Hi, I'm learning Bipolar Junction Transistor and need help to confusion which arise so I will keep posting questions which I don't understand to this thread. Thank you in advance. So my questions start: When using hybrid pi model and t model, we determine the dc operating point first. In one...