Recent content by aivilo775

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    Inertia from four masses connected by massless rigid rods

    Removing the 1/2 I used the equation above and got I = 0.008692
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    Inertia from four masses connected by massless rigid rods

    So I did I = Ia +Ib+Ic+Id. Since it's rotating through mass A, I set Ia = 0. I then did I = (.5)(230/1000)(8/100)^2 + (.5)(300/1000)(sqrt[(10/100)^2 + (8/100)^2)])^2 + (.5)(230/1000)(10/100)^2 I got that I = 0.004346 kg * m^2 Does this seem right? Or I suppose I shouldn't use the .5 so I =...
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    Angular Velocity from KE, radius, and mass

    This is the math I did when I rearrangedto solve for w, angular velocity. I used I = mr^2. I got w = 2.27995. The units would be the sqrt of(J /kg*m^2), which ends up just being 1/sec. to get the answer in rpm, I figured I would multiply w by 60sec (to get w = 136.797, but this wasn't right
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    Inertia from four masses connected by massless rigid rods

    I found xcm = 6.2cm, ycm = 4.9cm, but am unsure of how to tackle the inertia part of the problem.
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    Angular Velocity from KE, radius, and mass

    I tried using the equation w^2 = (4*K)/(mr^2) but I don't think this is right... I got my answer to be 3.2243 and that's not correct