Recent content by AssyriaQ

A quick question: when you fit, how are you plotting the data? You probably already know this, but you should plot the inverse susceptibility versus temperature. The Curie-Weiss behavior is then a linear relation. Also, what "different temperature range" did you use?

That is correct. You can, if you so prefer, use the principle \ln(\frac{a}{b})=\ln a - \ln b for the log in the denominator.

For part 1, no it is not correct. What you have written is a column matrix. Your other suggestion is correct. Have you done matrix multiplication before? You cannot multiply a 3x1 matrix and a 3x3 matrix. However, you can multiply a 1x3 and a 3x3. That is why it matters whether your write a...

t^{-1/2}=\frac{1}{t^{1/2}}.

Hi Raizy, Can you show how you are trying to solve this? If you show us, we can help you pinpoint where the problem is.

No, the base is 7-2=5 cm.

Correct.

There is no need to worry that much about factoring. You have \frac{1}{2}x^{2}-4=0. Simply solve for x to obtain the intercept.

Seems correct.

Just use the Pythagorean theorem to calculate the diagonal (which would be the hypotenuse). You already know the height, and you can easily find out the other cathetus (you more or less already have it since you wrote out coordinates).

Well, you need to show some work or at least show your thoughts on how to proceed. What have you done so far? Hint/question: What is nice about the trapezoid being isosceles?

Here is a hint: don't express x3 in terms of u. At first, express only the square root term and dx in terms of u and du. This will give you an easier term than x^3 to express in terms of u.

You have two unknown, R1 and R2, and you have two equations, one for the connection in series and one for the connection in parallel. With two unknowns and two equations, you can simply set up your system of equations and solve for R1 and R2. Can you write the two equations?

I am a little confused by the wording. What do you mean by "equivalent resistance"? Do you mean the total resistance or that they are equivalent (the same)? If it is the former, then why must they add up to 910 ohm? Don't they add up to 710 when connected in serial?

I was referring to when you integrated the sine with respect to y, and received a cosine. The lower integration limit is 0 so it cos(0) should not vanish. Edit: I see you discovered what I meant. It took 20+ minutes for this computer to load my reply!