Recent content by Atilla1982

I have: int (1/(sqrt -x^2 -2x))dx so I rewrite (-x^2-2x) --> 1-(x+1)^2 and swap those two. then I say t=x+1, and substitute that in. So now I have: int (1/(sqrt 1-t^2)) dt Here I get stuck, can anyone please help?

I have z=-(1/2)-(sqrt3/2)i r=|z| is this right? r=cos*2Pi/3+i*sin*Pi/3 = 1 + sqrt3/2*i Now I have to find Z^2004, how do I do that?

Ok, so the horizontal displacement does not count here? The work done by the man on the bag is the same as the work done by gravity on the bag? Thanks for taking the time to help me. No, there's no friction. I asked because he's walking upwards with an angle. But if I only need the vertical...

yes it's mass is 10kg. I know what displacement is, but he's not just moving in the vertical, but also the horizontal. His start coordinates are (0,0) and at the end (?,10). Surely it's not only the vertical displacement that I have to find? Or am I wrong?

A man is carrying a bag that weighs 10 kg. He's walking up a hill, when he stops he is 10 vertical meters higher. g = 9,8. I now have to find the work that's been done on the bag. I have W = m*g*d How do I find d?

A boy with a weight of 70 kg jumps down from a 3 meter high tree. His velocity on impact I have found to be 7,68 m/s and the impulse is 536,7kg*m/s. Now I need to find the average velocity during impact. What formula do I have to use?

In a fluid, there's an exponential force F = -b*e^v working against the direction of movement. B is constant, and v is the objects velocity in m/s. They want me to use Newtons 2. law to find a differential equation for the movement of an object with mass m. The equation is separable...

I'm lost here. Is it as simple as saying mg*sin30*0.40 + mg*cos30 = force needed to keep it moving at constant velocity?

A boy is pushing a 80 kg box along the floor. The force is exerted at the top of the box with an -30 degree angle with respect to the horizon. The kinetic friction is 0.40, and g is 9.8m/s^2. Find the force needed to keep the box moving with a constant velocity. 80kg = 784 N Force...

Thanx a lot all. I guess gokul's answer will put an end to our discussion, and my friend's arguments :smile:

yeah, there would be an overhang. The magnet and cart would be one, but there's a gap between them. My friend is still convinced that the cart will roll anyway. Can anyone please explain why it won' t ?

Me and my buddy had a discussion the other day. Imagine the scenario with the donkey that has a danglin carrot in front of him. If we swap the donkey for a cart and the carrot for a magnet, what would happen? My buddy was pretty sure that the cart would move, and I thought that it wouldn't...

And then set up an integral for time?

couldn't i do: R=Vi^2*sin2(THETAi)/g R=the length of the throw Solving for Vi= 21.72 m/s

2d Motion I've been stuck with this problem for a while. Appreciate if anyone can point me in the right direction. A boy stands in a field, he throws a stone with an initial 45 degree angle. The field has a 5 degree angle downwards, so the stone touches down at -5 degree angle and 82 meters...