Solving Indefinite Integrals: "int (1/(sqrt -x^2 -2x))dx

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SUMMARY

The forum discussion focuses on solving the indefinite integral of the function int (1/(sqrt(-x^2 - 2x)))dx. The user successfully rewrites the expression as int (1/(sqrt(1 - (x + 1)^2))) dt after substituting t = x + 1. The discussion emphasizes the importance of recognizing the derivative of the arcsine function to proceed with the integration. The key conclusion is that understanding trigonometric substitutions is essential for solving integrals involving square roots of quadratic expressions.

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  • Understanding of indefinite integrals
  • Familiarity with trigonometric substitutions
  • Knowledge of the arcsine function and its derivative
  • Basic algebraic manipulation skills
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  • Learn about trigonometric substitutions in integral calculus
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Atilla1982
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I have:


int (1/(sqrt -x^2 -2x))dx

so I rewrite (-x^2-2x) --> 1-(x+1)^2 and swap those two.

then I say t=x+1, and substitute that in.

So now I have:

int (1/(sqrt 1-t^2)) dt

Here I get stuck, can anyone please help?
 
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That was an excellent substitution. Review the derivative of the arcsine function.
 

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