Recent content by AtticusFinch

two similar sin waves travel together they form a single sin wave What you are talking about is interference. Due to lack of information you can't really use that in this problem. Decibels is the logarithmic scale of intensity. If you put two planes together (ignoring interference) the...

You couldn't produce a perfect sine wave because while a tuning fork produces just the fundamental frequency the human voice produces multiple harmonics in addition giving it it's distinctive sound. There's a good MIT online video with a professor putting the sound of several instruments...

If you believe in conservation of energy, the potential and kinetic energies of an escaping object will always add to zero. So when an object has lost 90% of it's initial kinetic energy... (1-0.90)\frac{1}{2}mv_e^2 + \frac{-GMm}{x} = 0 Hopefully that helps. Also, there's a couple of...

You wrote down the right equation. Notice that give you a rate of heat transfer so you can divide time over to the left side of the equation. Then it's just a substitution of information problem.

A couple of things could have gone wrong here, but from what I see they aren't math related. Either: 1) The frequency of the waves reflected from the whale (the waves that the whale is producing) is 23077 Hz. 23 kHz is the frequency of the waves reflected from the whale and heard by the...

The path length difference produces destructive interference at the point where he stands. What does that tell you about the wavelength (and frequency)?

Ah I see so you were using the product rule to get = t + a Well, good that you understand now :)

Yeah I'm not really sure why you think this: dv/dt = at =a't + at' =1(t) + a(1) = t + a works. Here's how you should see it. Equation 2-11 shows v as a function of time with initial velocity v0. In other words, v(t) = v = v0 + at Take the first derivative with respect to...

a = \frac{dv}{dt} a dt = dv \int a dt = \int dv at = v - v_0 at + v_0 = \frac{dx}{dt} atdt + v_0dt = dx \int atdt + \int v_0dt = \int dx \Delta x = v_0t + \frac{1}{2}at^2

Yeah, the equation x = vt is not accurate for an object with an acceleration. Perhaps that is why you are confused?

I did double check it when I first posted. Your answers are right but missing units. If your teacher wanted different units then perhaps therein lies your confusion.

That's what I'm saying. Your answer is wrong because you used the wrong number in your calculations. All you need to do is use the right one.

Current is simply protons moving in one direction. Moving charges in a magnetic field experience a force. Consequently the bar experiences a force. You've basically solved 90% of the problem with the two equations you wrote down. BIL = ma You can easily use the information given and...

Use the Pythagorean theorem to add the component Intensities and find the angle and magnitude of the total intensity. Then find the angle between the intensity vector and the sunglasses. Then use Malus' Law. Same applies for part b) with just a slight twist.

You can only move your head so far until the only light reaching your eye is light TIRing from the swimming pool's bottom. Find what angle you can tilt your head until this happens and find the corresponding horizontal distance moved from a initial position of looking straight up.