Light Polarization at the Beach: Understanding Sunbathers' Vision

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SUMMARY

The discussion focuses on the effects of light polarization at the beach, specifically how polarizing sunglasses impact the intensity of light received by a sunbather. The horizontal component of the electric field vector is 1.8 times the vertical component, leading to a specific calculation of light intensity using Malus' Law. The participants aim to determine the fraction of light intensity that reaches the sunbather's eyes before and after wearing the sunglasses, considering the orientation of the sunbather's position.

PREREQUISITES
  • Understanding of light polarization and electric field vectors
  • Familiarity with Malus' Law for light intensity calculations
  • Basic knowledge of trigonometry and the Pythagorean theorem
  • Concept of light intensity and its components
NEXT STEPS
  • Study Malus' Law in detail to understand its application in polarized light scenarios
  • Explore the mathematical derivation of light intensity using the Pythagorean theorem
  • Investigate the effects of different angles of incidence on polarized light
  • Learn about the physics of light reflection and refraction at water and sand surfaces
USEFUL FOR

Physics students, optical engineers, and anyone interested in the principles of light behavior and polarization effects in real-world scenarios.

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Homework Statement



At a beach the light is generally partially polarized due to reflections off sand and water. At a particular beach on a particular day near sundown, the horizontal component of the electric field vector is 1.8 times the vertical component. A standing sunbather puts on polarizing sunglasses; the glasses eliminate the horizontal field component. (a) What fraction of the light intensity received before the glasses were put on now reaches the sunbather's eyes? (b) The sunbather, still wearing the glasses, lies on his side. What fraction of the light intensity received before the glasses were put on now reaches his eyes?

I'm really confused and I'm sure I am thinking too hard. Can anyone get me started?

I know there is an equation
I = (I not)(cos squared theta)

Homework Equations





The Attempt at a Solution

 
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Use the Pythagorean theorem to add the component Intensities and find the angle and magnitude of the total intensity. Then find the angle between the intensity vector and the sunglasses. Then use Malus' Law.

Same applies for part b) with just a slight twist.
 

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