Fluids Physics Question: Calculating Density and Pressure of a Physics Book"

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SUMMARY

The discussion focuses on calculating the density and pressure exerted by a physics book with specific dimensions and weight. The book's density is calculated to be 1014 kg/m³ using the formula for mass derived from weight (18 N) divided by gravitational acceleration (9.81 m/s²). The pressure exerted on a desktop when the book lies face up is determined to be 30.9 Pa, while the pressure when balanced on its spine is calculated to be 2592 Pa, although a correction is suggested to use the height for the latter calculation.

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Homework Statement


A physics book has a height of 26.0 cm, a width of 22.4 cm, and a thickness of 3.10 cm.

(a) What is the density of the physics book if it weighs 18 N?
? kg/m3
(b) Find the pressure that the physics book exerts on a desktop when the book lies face up.
? Pa
(c) Find the pressure that the physics book exerts on the surface of a desktop when the book is balanced on its spine.
? Pa


Homework Equations



Divide the weight by gravity to get the mass.
18N/9.81 = 1.83 kg.
P = F/A

The Attempt at a Solution



Convert cm to meters:
(26.0cm)/100 = 0.26
22.4/100 = 0.224
3.10/100 = 0.031
Now divide
1.83/(0.26*0.224*0.031) = 1.83/0.00180544 = 1014 kg/m^3
P = F/A
area of the book = (0.224*0.26) = 0.5824 m^2
18/0.5824 = 30.9 Pa

When balanced on its spine, its width and thickness make up the area
(0.224*0.0310) = 0.006944
18/0.006944 = 2592 Pa
 
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You got the first two right, but I would say that you should use height in the last problem instead of width.
 
Like i said, I believe my answer is wrong. If someone would double check it.
 
That's what I'm saying. Your answer is wrong because you used the wrong number in your calculations. All you need to do is use the right one.
 

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