Recent content by ayalam

I got for r(t) r'(t)=<1,2t,3t^2> and for r'(0)=<1,0,0> But for r'(u)=<e^u,2e^2u,3e^3u> and r'(0)=<1,2,3> So i would assume the answer would be no?

Do different parametrizations of the same curve in R^3 result in identical tangent vectors at a given point on the same curve? Example may be helpful.

but wouldn't the \hbar/\sqrt{2} cancel out because of the other across the equal sign

That's true i can afford to pay the extra money my problem is that I will have the same professor for analytical mechanics, e&m, optics, and astrophysics. I had all this semester too. But i see your point with the money situation on how i can work that year and make more money. A girl is in my...

I have the oppurtunity to go to a another school for free but will have to stay there an extra year or I can stay at my current school and graduate in 1 year but will have to pay $12000 not sure which one will be the best choice. What do you strangers think?

How do you do it?

So if hbar were higher then momentums uncertainty will be higher. I understand that, i understand that the world would be different. For example I could walk to the store you can either know where I'm at (positon)or know my momentum never both. would that be the case? It makes sense to me that a...

1. Planch's constant[h bar] is really small, so small that in our macroscopic world we generally can't notice it. what if [h bar] were larger, what would our world be like if it were larger? How much larger would it have to be to so that macroscopic objects displayed "quantum behavior'. 2...

yes i did mean sho.

to get to the speed of light it takes an infinite amount of energy. Not possible. Read up on the twin paradox will help a little.

v=vnot+at vnot equals acceleration from the beginning of the problem. v= velocity at a given time.

How to determine the matrix representation of position & momentum operator using the energy eigenstates as a basis

look up the shrodinger equation