Velocity as a function of time?

AI Thread Summary
To determine the velocity of an object with a constant acceleration of 22.3 m/s² at an angle of 63.9 degrees East of South, one must derive a function v(t) that represents velocity over time. The relevant equation is v = v₀ + at, where v₀ is the initial velocity at time t=0 and a is the acceleration. It is crucial to recognize that velocity is a vector quantity, meaning both magnitude and direction must be considered. Clarification was provided that v₀ should not be confused with acceleration but rather the initial velocity. Understanding these concepts is essential for accurately calculating velocity as a function of time.
bullroar_86
Messages
30
Reaction score
0
if an object has an acceleration of 22.3 m/s^2 [63.9 degrees E of S]

what is its "velocity as a function of time"

not sure what that means.. any ideas?
 
Physics news on Phys.org
bullroar_86 said:
if an object has an acceleration of 22.3 m/s^2 [63.9 degrees E of S]

what is its "velocity as a function of time"

not sure what that means.. any ideas?

It means you have to find a function v(t) that relates the speed of the object, and the time elapsed.

Hint: The answer is in the definition of (constant) acceleration.
 
v=vnot+at
vnot equals acceleration from the beginning of the problem.
v= velocity at a given time.
 
ayalam said:
v=vnot+at
vnot equals acceleration from the beginning of the problem.
v= velocity at a given time.

No, in that equation, "vnot" has to be the velocity at t= 0. And be sure to note that the velocity is a vector, not just a number.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top