Recent content by Beez

Thanks for helping me again geosonel. I got it!

Woops Sorry, somehow I posted the same question twice. Please disregard this and leave your advice in the other one with the same title with (not time elapsed) added. Thanks.

Hi, I encountered the great difficulty solving the following question. (The reason why its is hard is because I have to express the velocity as a function of the distance of the object has traveled in stead of as a function of the time elapsed.) Starting from rest at t=0, an 8 lb. object is...

Hi, I encountered the great difficulty solving the following question. (The reason why its is hard is because I have to express the velocity as a function of the distance of the object has traveled in stead of as a function of the time elapsed.) Starting from rest at t=0, an 8 lb. object is...

Dear Geosonel: Thank you for helping me again! Well, I guess I didn't quite understanding the problem yet. Your explanation helped me a lot to understand what the problem ment. I will try to solve the equation tomorrow since my brain has been used too much today :blushing: Please wish me...

George: Thanks you for your help. My ability of English limited me to throughly comprehend this problem, I guess. Yes, I got the same answer, too. <-- OK, I lied. I thought I understood so I wrote this before actually solving the problem again. Shame on me but I couldn't get the same answer...

Hi, I have another problem that I couldn't solve. Q: The rate at which a certain substance dissolves in water is proportional at the product of the amount undissolved and the difference c1-c2, where c1 is the concentration in the saturated solution and c2 is the concentration in the actual...

I didn't know that Thanks for your help again Saltydog and thanks for the detailed explanation for the problem, Geosonel! I did not know the air is going out at the same rate (I thought the air density would increase = this concept got me). (Not all students are as smart as you, so I really...

Hello. I need a help again for my differential equations class. The problem is as follows: The air in a room whose volume is 10,000 cu ft tests 0.15% carbon dioxide. Starting at t=0, outside air testing 0.05% carbon dioxide is admitted at the rate of 5000 cu ft/min. (a) What is the...

I did it Everyone, you should be proud of me. With your help, I think I completely understood the mixing problem. The second part of the question was as follows b) If the capacityof the tank is 250 gal, what is the concentration at the instant the tank overflows? This is how I solved...

Thank you everyone. Well, at last it was not a math but English problem with me (my excuse is English is not my first language :smile: ) Yes, I understood what I missed. I also see that 7.8lb was the right amount of salt left in the tank as well. Sorry that I did not respond right away since...

Saltydog, I understood the problem you suggested me to take a look. Only the difference between mine and that problem is that instead of conc water, flesh water is added to the tank. That is why I thought IN = 0 Am I wrong?

Q: A large tank initially contains 100 gal of brine in which 10lb of salt is sissolved. Starting at t=0, pure water flows into the tank at the rate of 5 gal/min. The mixture is kept uniform by stirring and the well-stirred mixture simulaneously flows out at the slower rate of 2 gal/min. a)...

Sorry that I'm not that smart, but... Lurflurf, thanks for showing me how to solve the problem. I understood most of them, but could not understand x^2d(\frac{y}{x})=-ydx+xdy part in your

Mathload, yes you are right. I was suppose to be able to get IF by using the formula you provided. I also tried \frac{1}{P}[\frac{dq}{dx}-\frac{dp}{dy}], but did not work either. Please take a look at the following and offer me suggestions where I should go from there. Original equation...