Recent content by bobby.pdx

cool. thanks for the help

Oh you're completely right. Now I got (.169)^x. Now if I change 5nm to 50A I get (.169)^50=.287x10^-38. This is a way better answer even though it's not the same it's at least the same order of magnitude.

I made a mistake in that calculation. The answer I got from that equation is actually exp(-.097x) which is still not correct. Also I meant to write the unit of mass as keV/c^2

sorry I get exp(-.097x)

T(E)≈exp((-2/1.973keVA/c)√(2(511keV/c))∫(0.003keV)dx)=(0.907)^x It should look like 0.96x10^-38

I showed you exactly what I did. The first calculation under "3. The Attempt at a Solution". I put 0.03keV for U-E and I entered it exactly like that into my calculator. I told you the answer I got and the answer I'm looking for. Not sure how I can be any more specific.

That's what I did. Still gave me the same answer

Homework Statement Two conductors are separated by an insulator. Model the insulator as a square barrier of height 0.01 keV and a width of 5nm. Determine the transmission coefficients for electrons of 7,000 meV. The only thing is I have to use the approximation formula for finding the...

nevermind. I figured it out

I have an example problem in my book. I have uploaded an image. The part I can't figure out is how to do the last part of the problem to come up with the transmission coefficient. The book gives me a formula but when I plug in all the numbers from the formula into my calculator I get a...

This seems right. The only thing is the problem then asks to use this formula to calculate this kind of spread of spectral lines for both hydrogen and tritium for this spectral line with and without the reduced mass correction to the Bohr model of both hydrogen and tritium. If this formula is...

Let's say the lifetime of the excited state is 10^-7 seconds. How would I go about deriving the formula from there?

Homework Statement Derive from the uncertainty principle a formula for the relative spread of the spectral line that corresponds to the longest wavelength of the Lyman series. Homework Equations uncertainty principle: σxσp≥\hbar/2 planck constant \hbar=h/2pi h=λp Lyman series...