Approximate transmission coefficient of a square barrier

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Homework Help Overview

The discussion revolves around calculating the transmission coefficient for electrons encountering a square barrier modeled as an insulator between two conductors. The barrier has a specified height and width, and participants are required to use an approximation formula for the transmission coefficient.

Discussion Character

  • Mathematical reasoning, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the integral component of the approximation formula and question whether the difference (U-E) can be treated as a constant. There are discussions about the calculations leading to different values for the transmission coefficient and the implications of unit conversions.

Discussion Status

Several participants are actively engaging with the calculations and sharing their results. There is a recognition of mistakes in earlier calculations, and some participants are converging on similar values for the transmission coefficient, although no explicit consensus has been reached.

Contextual Notes

Participants are working under the constraints of homework guidelines, which may limit the types of assistance they can provide. There is an emphasis on understanding the mathematical expressions and ensuring correct unit usage throughout the discussion.

bobby.pdx
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Homework Statement


Two conductors are separated by an insulator. Model the insulator as a square barrier of height 0.01 keV and a width of 5nm. Determine the transmission coefficients for electrons of 7,000 meV.

The only thing is I have to use the approximation formula for finding the transmission coefficient of a barrier with arbitrary shape.

Homework Equations



T(E)≈exp((-2/hbar)√(2m)∫√(U(x)-E)dx)


The Attempt at a Solution



T(E)≈exp((-2/1.973keVA/c)√(2(511keV/c))∫(U(x)-E)dx)

I'm not sure what I'm supposed to do for the ∫(U(x)-E)dx part. I solved the problem using the formula for the transmission coefficient for a square barrier and I got T≈0.96x10^-38. I'm pretty certain this is correct because there was a very similar example in my book.

That formula had a (U-E) where I used 0.01keV-7000meV=.003keV

If I enter .003keV for U(x)-E then I would get ≈(.907)^x

And this is where I get stuck because I should somehow get an answer that is close to T≈0.96x10^-38
Any help would be appreciated!
 
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Isn't U-E a constant, so you can bring it outside the integral ?
 
That's what I did. Still gave me the same answer
 
Can't see it being done. Not telepathic and not clearvoyant. Show what you do, so we can discuss it...
 
I showed you exactly what I did. The first calculation under "3. The Attempt at a Solution". I put 0.03keV for U-E and I entered it exactly like that into my calculator. I told you the answer I got and the answer I'm looking for. Not sure how I can be any more specific.
 
T(E)≈exp((-2/1.973keVA/c)√(2(511keV/c))∫(0.003keV)dx)=(0.907)^x

It should look like 0.96x10^-38
 
sorry I get exp(-.097x)
 
bobby.pdx said:
T(E)≈exp((-2/1.973keVA/c)√(2(511keV/c))∫(0.003keV)dx)=(0.907)^x

Did you drop a square root somewhere? Compare what you wrote here with your original expression in the "Relevant Equations" section.

Note, you wrote the units of the mass of the electron as kev/c. Is this correct?
 
I made a mistake in that calculation. The answer I got from that equation is actually exp(-.097x) which is still not correct. Also I meant to write the unit of mass as keV/c^2
 
  • #10
I don't get .097. Again, did you drop a square root? I see a square root symbol occurring twice in

T(E)≈exp((-2/hbar)√(2m)∫√(U(x)-E)dx)
 
  • #11
Oh you're completely right. Now I got (.169)^x. Now if I change 5nm to 50A I get (.169)^50=.287x10^-38. This is a way better answer even though it's not the same it's at least the same order of magnitude.
 
  • #12
That's close to what I get, too. I get Exp[-1.77x] = Exp[-88.5] = .37x10-38
 
Last edited:
  • #13
cool. thanks for the help
 

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