Recent content by bobby3280
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Voltage potential due to 2 charges
Wow how'd I miss that thanks!- bobby3280
- Post #3
- Forum: Introductory Physics Homework Help
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Voltage potential due to 2 charges
Homework Statement Find the potential at points a and b in the diagram for charges Q1 = +1.60 nC and Q2 = -1.60 nC. I know b is 0 Homework Equations V = kQ/r The Attempt at a Solution I tried this using the equation and got 8.99e9 * [( +1.60e-6 / .05) + ( -1.60e-6 / .15...- bobby3280
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- Charges Potential Voltage
- Replies: 2
- Forum: Introductory Physics Homework Help
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How do you find the mass of a vibrating metal wire on a piano?
Thanks found the equation and answer.- bobby3280
- Post #3
- Forum: Introductory Physics Homework Help
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How do you find the mass of a vibrating metal wire on a piano?
Homework Statement The longest "string" (a thick metal wire) on a particular piano is 3.0 m long and has a tension of 300.0 N. It vibrates with a fundamental frequency of 27.4 Hz. What is the total mass of the wire? ( in kg) Homework Equations The only relevant equation I could find is...- bobby3280
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- Frequency Mass Waves
- Replies: 2
- Forum: Introductory Physics Homework Help
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Calculating Torque & Work on a Flywheel of Mass 183kg & Radius 0.63m
A flywheel of mass 183 kg has an effective radius of 0.63 m (assume the mass is concentrated along a circumference located at the effective radius of the flywheel). (a) What torque is required to bring this wheel from rest to a speed of 120 rpm in a time interval of 34.3 s? (b) How much...- bobby3280
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- Wheel Work Work done
- Replies: 2
- Forum: Introductory Physics Homework Help
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Calculate Speed of Light & Heavier Car After Collision at Intersection
Wow don't know how i missed that but thanks a lot!- bobby3280
- Post #7
- Forum: Introductory Physics Homework Help
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Calculate Speed of Light & Heavier Car After Collision at Intersection
The last part of the question states The speed limit for each car was 70 km/h. And I know that only the lighter car was speeding. So V1i > 70 km/s When i solve for my initial velocities using 19.8 and this formula V1i = ((m1 + m2) / m1) Vf cos 30 putting in 19.8 i get V1i = 36.8 km/s...- bobby3280
- Post #5
- Forum: Introductory Physics Homework Help
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Calculate Speed of Light & Heavier Car After Collision at Intersection
F = .8 m g F = .8 * 2435 * 9.8 F = 19090.4 N a = F/m a = 19090.4 / 2435 a = 7.84 m/s I think this is right but not sure after. Vf^2 - Vi^2 = 2ax setting Vf to 0 I get a Vi = 19.8 and i know this Velocity is too slow?- bobby3280
- Post #3
- Forum: Introductory Physics Homework Help
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Calculate Speed of Light & Heavier Car After Collision at Intersection
A police officer is investigating the scene of an accident where two cars collided at an intersection. One car with a mass of 1135 kg moving west had collided with a 1300 kg car moving north. The two cars, stuck together, skid at an angle of 30° north of west for a distance of 25 m. The...- bobby3280
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- Car Car crash Crash Momentum
- Replies: 6
- Forum: Introductory Physics Homework Help
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Work done by a spring when stretched
Thanks, I had the minus sign because that is how the formula is in the book.- bobby3280
- Post #3
- Forum: Introductory Physics Homework Help
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Work done by a spring when stretched
I have a simple problem that i can't seem to get right. An ideal spring has a spring constant k = 22.0 N/m. What is the amount of work that must be done to stretch the spring 0.70 m from its relaxed length? I tried W = (-)1/2 k x^2 = - (.5)(22.0) (.7^2) =...- bobby3280
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- Spring Work Work done
- Replies: 7
- Forum: Introductory Physics Homework Help