bobby3280 said:Homework Statement
Find the potential at points a and b in the diagram for charges Q1 = +1.60 nC and Q2 = -1.60 nC.
I know b is 0
Homework Equations
V = kQ/r
The Attempt at a Solution
I tried this using the equation and got
8.99e9 * [( +1.60e-6 / .05) + ( -1.60e-6 / .15 ) ] = 191700 V but this isn't right any suggestions??
The formula for calculating voltage potential due to 2 charges is V = k(q1/q1)/r1 + k(q2/q2)/r2, where V is the voltage potential, k is the Coulomb's constant, q1 and q2 are the charges, and r1 and r2 are the distances between the charges and the point where the voltage is being calculated.
The voltage potential is inversely proportional to the distance between the charges. This means that as the distance between the charges increases, the voltage potential decreases.
Yes, the voltage potential can be negative. This occurs when the charges have opposite signs and are attracting each other. In this case, the potential energy of the system decreases, resulting in a negative voltage potential.
The unit of measurement for voltage potential is volts (V). This unit is derived from the formula for voltage potential, which includes the unit of charge (coulombs) and the unit of distance (meters).
Voltage potential and electric potential energy are related but different concepts. Voltage potential is the amount of potential energy per unit charge at a specific point in an electric field. Electric potential energy, on the other hand, is the total potential energy of a system of charges. In other words, voltage potential is a measure of the strength of the electric field at a single point, while electric potential energy is a measure of the total energy stored in an electric field.