Recent content by bowma166

You could do something like a magnetic or electric field simulator/calculator with visualizations?

Yes, as tjkubo said, for this problem you can't simply say \Phi_B=BA\cos\theta but instead must use \Phi_B=\int\vec{B}\cdot\textrm{d}\vec{A} How would you write \textrm{d}\vec{A} in terms of dy in this problem?

Anyone?

Homework Statement Two sheets of polaroid are aranged as polarized and analyzer. Suppose that the preferential direction of the second sheet is rotated by an angle \phi about the direction of incidence and then rotated by an angle \alpha about the vertical direction. If unpolarized light of...

Looks to me like the vertical position would have a uniform negative second derivative, and the horizontal position would have a uniform positive third derivative, perhaps? i.e. x=\frac{1}{6}kt^{3}+\frac{1}{2}a_{0}t^{2}+v_{0}t+x_{0} where k is the constant third derivative

Today, my professor said something like "The series 1 + -1 + 1 + -1 and so on is defined to be one half... but let's not go into that." and then didn't feel like explaining when people asked him why. I have no idea why that would be true... It seems like a similar case might be...

Well, as you're pulling in the tether, angular momentum is conserved. Angular momentum: L=mvr, so: mvr_{1}=mvr_{2} rewriting v as wr... \omega_{1} r_{1}^{2}=\omega_{2} r_{2}^{2} With \omega_{2}=2\omega_{1}, we get r_{1}^{2}\omega_{1}=r_{2}^{2}\left(2 \omega_{1}\right)...

Well... the de broglie equation is \lambda=\frac{h}{p}. I don't really think that p=mv works for light, because photons have no mass. I don't really know what I'm talking about though.

Bump. This problem sucks, I know. :\

The way I would go about doing this problem--I don't know if it's the best way--is to say the cylinder has a mass m, then figure out the volume of water needed to equal this mass. You can then equate this to a formula for mass of the cylinder.

Bump.

Homework Statement A flexible rope of length l and mass m hangs between two walls. The length of the rope is more than the distance between the walls, and the rope sags downward. At the ends, the rope makes an angle of \alpha with the walls. At the middle, the rope approximately has the shape...

The problem I'm having is deciding on whether to do a pure science (probably physics or chemistry; mathematics might be too pure even though i love it) or engineering. I'm currently finishing up my fall semester of freshman year... I love physics and math the most, and also have a strong liking...

Oh, whoops. Thanks.

Isn't the equation for angular velocity \omega=\omega_{0}+\alpha t? I think you're confusing it with \phi=\phi_{0}+\omega t+\frac{1}{2}\alpha t^{2}