What is the mass density of a submerged cylinder?

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Homework Help Overview

The problem involves determining the mass density of a submerged cylinder that floats in water. The cylinder's dimensions and the conditions of floating are provided, but the approach to finding its density is under discussion.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between buoyancy and density, questioning how to find the volume of the cylinder without knowing its radius. Some suggest using variables to express the radius in equations, while others discuss the relationship between the mass of the cylinder and the volume of displaced water.

Discussion Status

The discussion is active with various approaches being considered. Some participants offer guidance on how to set up equations involving the cylinder's mass and the volume of water displaced. There is a recognition that certain variables may cancel out, allowing for a solution without needing all dimensions explicitly defined.

Contextual Notes

Participants note confusion regarding the application of formulas and the relationship between the cylinder's dimensions and its density. The problem constraints include the requirement to find density without direct measurements of all dimensions.

cyclemun
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Homework Statement


A 6.40 cm-tall cylinder floats in water with its axis perpendicular to the surface. The length of the cylinder above water is 1.00cm.

Homework Equations


What is the cylinder's mass density?


The Attempt at a Solution


Well, I am confused because I can use the equation for buoyancy to find the mass of the cylinder, but I don't know how to find its volume.
 
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You don't need the radius of the cylinder to find the volume. The question only asks for its density. Just write out the equation using 'r' to denote the unknown radius and something will cancel out.
 
so would i use the forumula F = rho* V * g?
 
The way I would go about doing this problem--I don't know if it's the best way--is to say the cylinder has a mass m, then figure out the volume of water needed to equal this mass. You can then equate this to a formula for mass of the cylinder.
 
cyclemun said:
so would i use the forumula F = rho* V * g?
You still need to break V up in terms of r and h.
 
Weight of the cylinder= Area*6.4 cm*density*g
Weight of the displaced water= Area*5.4*1000*g
Now find the density.
 
I have the same problem just different numbers... I am confused on what to do. F=rho*v*g
then after you cancel out you get
F=mhg right? is that the force on the bottom?
 
For a floating object the fraction of the volume of a floating object that is below the fluid surface is equal to the ratio of the density of the object to the density of the fluid:

V-f/V-o=rho-o/rho-f as has been noted, the radius cancels, you know rho-f, you can solve directly for rho of the object.
 

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