Right, so if I take energy of pendulum equation as
PE = mgL(1 – COS θ)
Mass should be irrelevant for this(?)
9.81*1*(1-cos(140))=13.2
9.81*1*(1-cos(30))=7.5
= 5.7j change
KE=1/2mv^2
2KE=mv^2
sqrt(2KE)=mv
Ignore M, so that V = sqrt(2*5.7)
=3.38m/s
Is that looking ok?
Out of school, AS level Math.
This isn't homework, just a practical problem I'm trying to get my head around.
All of my usual point of calls don't like pendulums that go above the horizontal (I guess GCSE assumes it's made of string) and I can only find equations for Vmax.
I'm having no problem finding the maximum speed of a pendulum but I'm not sure when I move its start point and measure point.
I would like to know the speed of a pendulum at 30 degrees that has been dropped at 140 Degrees. I'm just giving some numbers to explain that it is above the horizontal...