Recent content by Buzzlastyear
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Curve Sketching: Solving for b and d: f(x)=x^3+bx^2+d
Oh yeeesss! Thank you! I knew i would have to get two unknowns from somewhere then solve!- Buzzlastyear
- Post #4
- Forum: Calculus and Beyond Homework Help
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Curve Sketching: Solving for b and d: f(x)=x^3+bx^2+d
Homework Statement f(x)=x^3+bx^2+d given a critical point of (2,-4), solve for b and d Homework Equations f'(x)=3x^2+2bx ? The Attempt at a Solution I wasn't really sure where to go with this. So I know that a critical point happens when f'(x)=0, and this point can be either...- Buzzlastyear
- Thread
- Curve
- Replies: 3
- Forum: Calculus and Beyond Homework Help
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Derivative of f(x)=sqrt(7+sqrtx^3)
So would it now be f'(x)=(1/(2√7+√x^3))((3/2)x^(1/2))?- Buzzlastyear
- Post #4
- Forum: Calculus and Beyond Homework Help
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Derivative of f(x)=sqrt(7+sqrtx^3)
Ah yes, thank you!- Buzzlastyear
- Post #3
- Forum: Calculus and Beyond Homework Help
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Derivative of f(x)=sqrt(7+sqrtx^3)
Homework Statement Determine the derivative of f(x)=√(7+√x^3) Homework Equations Chain rule: f(x)=fog(x) f'(x)=f'(g(x)) x g'(x) The Attempt at a Solution f(x)=√(7+x^(3/2)) f'(x)=((½)x^(-½))(7+x^(3/2))((3/2)x^(½)) =(3.5x^(-½)+½x)((3/2)x^(½)) =5.25x^0+¾x^½ =5.25+¾x^½ That's as far as i got...- Buzzlastyear
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- Derivative
- Replies: 5
- Forum: Calculus and Beyond Homework Help
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Finding the derivative of m(x)=-e^xcosx
Okay, thanks very much for your help.- Buzzlastyear
- Post #6
- Forum: Calculus and Beyond Homework Help
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Finding the derivative of m(x)=-e^xcosx
And as for using the product rule, would this be correct? m'(x)=-e^x*(cosx) + (-sinx)(-e^x) assuming my previous post is correct?- Buzzlastyear
- Post #4
- Forum: Calculus and Beyond Homework Help
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Finding the derivative of m(x)=-e^xcosx
Okay, thank you. I had not learned about the derivative of exponential functions but looked it up. So is -e^x still just -e^x?- Buzzlastyear
- Post #3
- Forum: Calculus and Beyond Homework Help
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Finding the derivative of m(x)=-e^xcosx
Homework Statement Find the derivative of m(x)=-e^x*cosx at x=1 graphically and algebraically. Homework Equations The Attempt at a Solution So first i just attempted to find the derivative: m'(x)=-xe^(x-1)*(-sinx)----> is this correct? so to find at x=1 i just sub in 1...- Buzzlastyear
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- Derivative
- Replies: 5
- Forum: Calculus and Beyond Homework Help
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Scalar Equation of Plane Determining the value of k
Homework Statement Determine the value of k so that the line with parametric equations x = 2 + 3t, y = -2 + 5t, z = k is parallel to the plane with equation 4x + 3y – 3z -12 = 0. Homework Equations The Attempt at a Solution let k=a + bt x=2+3t y=-2+5t z=a+bt direction...- Buzzlastyear
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- Plane Scalar Value
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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Equations of a Plane: Determining if a line lies within a plane
Thank you- Buzzlastyear
- Post #3
- Forum: Calculus and Beyond Homework Help
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Equations of a Plane: Determining if a line lies within a plane
Homework Statement Does the line with equation (x, y, z) = (5, -4, 6) + u(1,4,-1) lie in the plane with equation (x, y, z) = (3, 0, 2) + s(1,1,-1) + t(2, -1, 1)? Show algebraically. Homework Equations The Attempt at a Solution I really have no idea where to start so I put the equations into...- Buzzlastyear
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- Line Plane
- Replies: 2
- Forum: Calculus and Beyond Homework Help
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Plane Equations with Vector and Parametric Forms | Homework Solution"
Homework Statement Determine vector and parametric equations for the plane containing the point A(2, 3, -1) and parallel to the plane with equation (x, y, z) = (2, 1, -3) + s(5, 2, -1) + t(3, -2, 4). Show your work. Homework Equations The Attempt at a Solution I think my answer is...- Buzzlastyear
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- Plane
- Replies: 2
- Forum: Calculus and Beyond Homework Help
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What are the equations for a line in 3-space passing through two given points?
Homework Statement Determine vector, parametric and, if possible, symmetric equations for the line through Q(2, -1, 3) and the mid-point of the line segment from L(3, -2, 5) to M(1, 4, -7). Homework Equations Midpoint equation=( (x1+x2)/2, (y1+y2)/2, (z1+z2)/2) The Attempt at a...- Buzzlastyear
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- Lines
- Replies: 1
- Forum: Calculus and Beyond Homework Help