1. The problem statement, all variables and given/known data Determine the value of k so that the line with parametric equations x = 2 + 3t, y = -2 + 5t, z = k is parallel to the plane with equation 4x + 3y – 3z -12 = 0. 2. Relevant equations 3. The attempt at a solution let k=a + bt x=2+3t y=-2+5t z=a+bt direction vector= (3,5,b) The normal to the equation 4x + 3y – 3z -12 = 0 is n=(4,3,-3) Dot product of the direction vector and normal: (4,3,-3).(3,5,6)=0 12+15-3b=0 b=9 therefore z=a+9t So: x=2+3t y=-2+5t z=a+9t not sure where to go from here Thanks for any help!