Scalar Equation of Plane Determining the value of k

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SUMMARY

The discussion focuses on determining the value of k for the line defined by the parametric equations x = 2 + 3t, y = -2 + 5t, z = k to be parallel to the plane described by the equation 4x + 3y – 3z - 12 = 0. The normal vector of the plane is identified as n = (4, 3, -3), and the direction vector of the line is (3, 5, b). The dot product condition for parallelism leads to the conclusion that b must equal 9, resulting in the equation z = a + 9t. The value of a can be any real number except for a specific case where the line lies on the plane, which occurs when a = 10/3.

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Homework Statement



Determine the value of k so that the line with parametric equations x = 2 + 3t, y = -2 + 5t, z = k is parallel to the plane with equation 4x + 3y – 3z -12 = 0.

Homework Equations





The Attempt at a Solution



let k=a + bt

x=2+3t
y=-2+5t
z=a+bt

direction vector= (3,5,b)

The normal to the equation 4x + 3y – 3z -12 = 0 is n=(4,3,-3)

Dot product of the direction vector and normal: (4,3,-3).(3,5,6)=0
12+15-3b=0
b=9
therefore z=a+9t

So:

x=2+3t
y=-2+5t
z=a+9t

not sure where to go from here

Thanks for any help!
 
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The line you got is parallel to the plane for any value of a, maybe except the one where this line is on the plane (that seems to be when a=10/3). There is nothing wrong here.
 

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