Recent content by carmen77

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    Designing Class A Amplifier with 12V Power Supply

    Homework Statement Designing a Class A amplifier for project with high voltage gain and high efficency or at least as high as we can get. It has to have a 12V power supply. We have the design but the when we add the power supply that converts the 120v ac to 12v dc our output voltage goes...
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    Designing a Class A Amplifier for Good Speakers, Inc.

    [b]1. Homework Statement EE3350 Electronics I Term Project "Power Amplifier Design" Objective: You will be designing a proper power amplifier for Good Speakers, Inc. The company will accept only two designs. One of them is Class A amplifier and the other one will be a Class B amplifier...
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    Electricity and Magnetism Question

    Part B W=\DeltaKE=-\DeltaU Vq=U In part A we found out that the potential difference at point C is V=2kq/L U=(2kq/L)*Q=2kqQ/L W=-\DeltaU=-2kqQ/L
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    Electricity and Magnetism Question

    I definently could be wrong as I'm taking physics 2 right now and will have to drop it haha but here's my shot at part A. Since V=kq/r (assuming V=0 at infinity), and potential difference is a scalar quantity, meaning direction doesn't have to be taken into account, then to find the potential...
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    Why Can't Percent Oxygen Be Directly Determined from Combustion Products?

    Ah, so the oyxgen comes from the sample and the oyxen it reacts with and that's why you can't find the oxygen of the sample from a calculation of the oyxgen in the products.
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    Why Can't Percent Oxygen Be Directly Determined from Combustion Products?

    44g CO2 * (1 mole CO2/44g CO2)=1 mole CO2 * (2 mole O/1 mole CO2)*(16g O/1 mole O)= 32g O in 44g of CO2 Did the same for C and got 12 g C in 44g of CO2 18g H20 * (1 mole H20/18g H2O)= 1 mole H20 * (1 mole O/1 mole H2O) * (16g O/1 mole O)= 16g O in 18 g H2O 2g H in 18g H2O Now...
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    Why Can't Percent Oxygen Be Directly Determined from Combustion Products?

    I don't know much about chemistry but is that because the sample undergoes a reaction in the presence of Oxygen O2 and a spark and produces CO2 and H20, so therefore, one couldn't obtain the mass of oyxgen in the sample from the addition of the mass of oyxgen in CO2 and the mass of oxygen in...
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    Why Can't Percent Oxygen Be Directly Determined from Combustion Products?

    That would be C-C bonds or C-H bonds often in combination with oyxgen, nitrogen, sulfur, and other elements but most that I have come across so far have only included the elements C, H, and O.
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    Why Can't Percent Oxygen Be Directly Determined from Combustion Products?

    Conceptual--Combustion of a sample Homework Statement When a sample is burned in a combustion train, the percent oxygen in the sample cannot be determined directly from the mass of water and carbon dioxide. Why? Homework Equations The Attempt at a Solution I'm working through...
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    L' Hospital's Rule Application

    Jeez again, man our teacher is really making us grind out these calculations...well okay thank you fellas.
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    L' Hospital's Rule Application

    Homework Statement \lim_{x\rightarrow 0} \frac{xe^2x+xe^x-2e^2x+2e^x}{(e^x-1)^3} Homework Equations L' Hospital's Rule \lim_{x\rightarrow 0}\frac{f(x)}{g(x)}= \lim_{x\rightarrow\0} \frac{f'(x)}{g'(x)} The Attempt at a Solution Phew, I think my hold on the latex codes are solid now, thanks...