Recent content by cemar.

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    Equation of plane through point P containing line L

    I am facing a similar problem right now, and i understand most of it, however, i am just having a hard time seeing how PQ * PR = normal of the plane Thank you!
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    What is the difference between converging and diverging functions?

    Can someone please explain the difference between a converging and a diverging function and how to recognize when each occur?? Thank you!
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    Antiderivative of arctan and x function (by parts maybe? )

    alright so gave er a shot (or a hundred). Heres where I am at : After first integration by parts: x^2arctan(8x) - 8 * { (x^2)/(1+64x^2) Now only the second part integration by parts: -8 * { (x^2)/(1+64x^2) dv = 1 / (64x^2+1) u = x^2 v = arctan(8x)/8 du=...
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    Antiderivative of arctan and x function (by parts maybe? )

    antiderivative of arctan and x function (by parts... maybe??!) find antiderivative of 2xarctan(8x) { = antiderivative s thing. I did it by parts at first and got x^2arctan(8x) - 8 * { (x^2)/(1+64x^2) To get the antiderivative of the second part i did it by parts again and that...
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    What is the antiderivative of (1-cos(t/6))^3 * sin(t/6)?

    Hey guys! So i have to find the antiderivative of (1-cos(t/6))^3 * sin(t/6) I have tried a bunch of different ways like by parts, trig substitution, identities, u-substitution then developing it, etc. but i just can't get it! Can some one just tell me the proper method to use after that I am...
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    Finding Solutions to Second Order Differential Equations with Initial Conditions

    y'' - 8y' + 16 = 0 ; y(0) = 4 ; y'(0) = 9 this should be not too bad but I am stuck in the same place. m^2 - 8m + 16 m1 = m2 = 4 y = C1e^(mx) + C2(e^(mx)) sub in y(0) = 4 4 = C1 + C2 C1 = 4-C2 y' = mC1e^(mx) + mC2e^(mx) sub in y'(0) = 9 9 = mC1 + mC2 C1 = 4 - C2...
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    Antiderivative of square root function

    thats really cool! I've never seen that formula before!
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    Antiderivative of square root function

    okay so it was actually a really dumb sneaky mistake: after all the subtituting and manipulating was done instead of 9cos^2(t) its actually supposed to be 81cos^2(t) then follow my steps from there and its right!
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    Antiderivative of square root function

    Ps any tips you might have would really help me out it doesn't have to be too in detail I am usually pretty good at this stuff. Thank you!
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    Antiderivative of square root function

    1. find the antiderivative of sqrt(81-x^2) in the bounds 0 to 9/2 okay so the first thing i did was sin substitution. where I made x = 9sin(t) dx = 9cos(t) where t is theta. then after some manipulating i got that that new integral was 9cos^2(t) i then used the double angle formula and...
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    Finding the Antiderivative of a Reciprocal: Step-by-Step Guide

    **her. And thanks I am definitely planning on getting the hardcore review on after that slightly embarassing display of where I am at in calculus right now. And for the record sledgehammers are a lot funner to use than nutcrackers. =)
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    Finding the Antiderivative of a Reciprocal: Step-by-Step Guide

    oh gosh. IIIII'm just going to go hang myself right now. Ill just use the excuse that I am smack dab in the middle of midterms thus in the state of mind that every thing is harder than it should be. Thanks ... i definitely won't let myself make the same mistake again.
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    Finding the Antiderivative of a Reciprocal: Step-by-Step Guide

    1. Find the antiderivative of 1/(x+3)^2 Okayy i knwo this is an easy problem but i COMPLETELY forget how to do it. Ive tried using partial fractions but it doesn't seem to be working. I just need to know how to start the problem then i should be alright from there. Thank you!
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