Recent content by ChetBarkley

Well if it were one particle hitting something, like a wall, then what would the 0.100kg and the -30m/s represent?

So far for the word problem I have: A 100 g particle, traveling at 40 m/s, collides inelastically with another 100g particle traveling towards it at 30 m/s. Now from the equation provided we need the question to ask us to find delta t, and that's simple enough but I'm not sure what that 1/2 is...

Are the starting and ending points of my equations from when the engines are ignited to when the rocket is no longer in contact with the spring?

Part A) So from a force diagram we can see that the only two forces acting in our system are the spring force(positive y axis) and the weight of the rocket(negative y axis), which means the spring force is equal and opposite to the weight force. The weight is simple enough ##12* 9.8=117.6N##...

Summary:: A 90 kg firefighter needs to climb the stairs of a 20-m-tall building while carrying 40kg of gear. How much power does he need to reach the top of the building in 55s. So first the total mass of our system is 130 kg. Using this mass, I found the potential energy the firefighter would...

It's when the ball is moving when parallel to the ground, giving ##v_{0 y}=0##.

It's given in the problem

So delta y = 0.2 and there is not velocity in the y direction once the string is cut, meaning v naught y is zero. So my equation looks like 0.2 = 0t+.5(9.8)t^2. Solving for t: t=sqrt(.2/4.9)

So delta y = 0.2 and there is not velocity in the y direction once the string is cut, meaning v naught y is zero. So my equation looks like 0.2 = 0t+.5(9.8)t^2. Solving for t: t=sqrt(.2/4.9).

So first I found the velocity of the ball at the bottom of the swing from the force equations, which I got to be 4.9 m/s and this is only in the x-direction. Then using the projectile motion for delta y I found time, which is 0.2s. Then using that time I found the delta x to be 0.98m. I just...