Recent content by chibi_lenne
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Images and Lenses (explanation needed please)
Thanks very much for clearing that up- chibi_lenne
- Post #4
- Forum: Introductory Physics Homework Help
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Images and Lenses (explanation needed please)
Okay, so I have to do a Lab Report, easy enough, I've done them before, but it isn't so clear, and when I tried doing it, I wasn't sure if I was even doing it right. (Personal Note: DO NOT TAKE PHYSICS CORRESPONDANCE! ><) Anyway, here's what I have to do. The Lab Report is on the...- chibi_lenne
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- Images Lenses
- Replies: 3
- Forum: Introductory Physics Homework Help
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Actual Depth and Apparent Depth
Yay! Thanks so much! I really appreciate the help and for you putting up with my massive brain malfunction ^_^()- chibi_lenne
- Post #20
- Forum: Introductory Physics Homework Help
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Actual Depth and Apparent Depth
*mutters something about incompitant calculators* So it should be something like this? \sin \theta_i = (n_i / n_R)\sin \theta_R = (1.00 / 1.33 )(\sin45*) = (0.7519)(0.7071) = 0.5317 \theta_i = 32.1*...- chibi_lenne
- Post #18
- Forum: Introductory Physics Homework Help
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Actual Depth and Apparent Depth
gah what am I doing wrong? x.x- chibi_lenne
- Post #16
- Forum: Introductory Physics Homework Help
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Actual Depth and Apparent Depth
0.8509 = \sin45* Or at least that is what I was doing...- chibi_lenne
- Post #14
- Forum: Introductory Physics Homework Help
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Actual Depth and Apparent Depth
ooo I see, (forgot to put in an extra set of () ) so it should be: \sin \theta_i = (1.00/1.33) (0.8509) = 0.6398 \theta_i = 39.6* ??- chibi_lenne
- Post #12
- Forum: Introductory Physics Homework Help
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Actual Depth and Apparent Depth
duh *slaps forhead* alright I have to rearrange the formula, I feel stupid now. So it should be: (ni)(sin{angle}i) = (nR)(sin{angle}R) so therefore sin{angle}i = (ni)/(nR)(sin{angle}R) ?- chibi_lenne
- Post #10
- Forum: Introductory Physics Homework Help
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Actual Depth and Apparent Depth
okay, so I have to find the angle of incidence...so how do I do that? x.x- chibi_lenne
- Post #8
- Forum: Introductory Physics Homework Help
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Actual Depth and Apparent Depth
Now I'm confused...how is d = 2.0m? if I did the equation for actual depth with that as d, it would mean the actual depth is the same as the apparent depth? Actual depth = (2.0m)/tan45* = (2.0m)/(1.0) = 2.0m- chibi_lenne
- Post #6
- Forum: Introductory Physics Homework Help
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Actual Depth and Apparent Depth
I decided to give my brain a bit of a rest on this problem and moved forward. I think I may have it, I'd still like to see if it's accurate or get help if it's completely wrong (which is very likely) Here's what I have so far: Analysis: n[i] = 1.33 for water n[2]= 1.00 for air Actual...- chibi_lenne
- Post #4
- Forum: Introductory Physics Homework Help
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Actual Depth and Apparent Depth
Okay, I need a bit of a jump start with this question, I know how to find the Apparent depth normally, but I've never done actual depth and I can't really figure it out (*stupid*) 11. Frederika is sitting in her fishing boat observing a rainbow trout swimming below the surface of the water...- chibi_lenne
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- Apparent depth Depth
- Replies: 19
- Forum: Introductory Physics Homework Help
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Discovering the Index of Refraction: A Quick and Easy Guide"
my brain is fried...and I need help again. How do I find the index of refraction again??- chibi_lenne
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- Index Index of refraction Refraction
- Replies: 2
- Forum: Introductory Physics Homework Help
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Calculating Wavelength in Water for Electromagnetic Radiation
Yay, thanks so much that was just driving me nuts- chibi_lenne
- Post #3
- Forum: Introductory Physics Homework Help
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Calculating Wavelength in Water for Electromagnetic Radiation
Seriously, if I didn't need physics I probably wouldn't take it.I've don the work for this one problem, but then I'm not sure if it's the right formula for what I need. Here's what I have so far(the parts in bold are the work I've done) 10. An electromagnetic radiation has a frequency of 5.00...- chibi_lenne
- Thread
- Replies: 2
- Forum: Introductory Physics Homework Help