Calculating Wavelength in Water for Electromagnetic Radiation

[chibi_lenne]

Seriously, if I didn't need physics I probably wouldn't take it.I've don the work for this one problem, but then I'm not sure if it's the right formula for what I need. Here's what I have so far(the parts in bold are the work I've done)

10. An electromagnetic radiation has a frequency of 5.00 x 10^14Hz.
b) Calculate its wavelength in water.

Given: wavelength = 0.6 x 10^-6m or 600nm

n = 1.33 for water​

Required: wavelength(med)
Analysis: c=(f)(wavelength{vac}) and c=(n)(wavelength{med})

therefore wavelength(vac) = (n)(wavelength{med}) and​

wavelength(med) = wavelength(vac)/n​

Solution: wavelength(med) = (0.6 x 10^-6m)/1.33

= 4.51 x 10^-7 or 451 nm​

​

Now I get looking at this and I'm not sure if that's exactly how I go about doing this or if this is what I'm supposed to do for finding the index of refraction (which comes later) Please help, my brain is fried.

 

[Chi Meson]

You are correct. Remember, the wavelength of any frequency of light is always longest in a vacuum, shorter in a medium. Frequecy of the light stays constant.

 

[chibi_lenne]

Yay, thanks so much that was just driving me nuts