Recent content by chimath35

I mean it assumes that x>0. The problem did not state that although I guess it is just assumed considering it is real analysis.

Thanks, yeah I have done this proof before. I just made a mistake thinking about negatives when clearly root x plus root a is always positive and therefore can be pulled out of the abs val

never mind I figured out, but thanks for the replies

sorry I meant you can't assume root x plus root a is positive, if say c∈ℝ and c>0 then abs val(c⋅x)=c⋅abs val(x)

also a>0

let f(x) equal root x show that as x→a lim f(x) equals root a

but the abs val goes away on the denom. that is what I don't understand, you can't assume root x - root a is positive

I have done this problem before but forgot how to get from one step to the next: let a>0. how is absval(x^1/2-a^1/2) equal to abval(x-a)/(x^1/2-a^1/2)?

Thanks

I am applying for a PhD program in statistics and I want a full assistantship. Should I check the box to apply for additional financial aid or will that affect an assistantship chance? Thanks.

Thanks. I will be finishing a bachelor's degree in mathematics this year. I have very basic non calc based statistic knowledge although I do have some calc based and even joint density probability knowledge. I thoroughly enjoy real analysis and I will be doing independent study this year in real...

Could you please list and elaborate as much as you can on schools that are heavy on the theoretical side of statistics? Thank you as I have to have my applications in by December-January for grad school (I plan to enter a PhD program and would like guaranteed funding).

Thanks. I thought about that and I probably will post at a couple universities in the area.

Nice, thank you.

Thanks, sounds good.