Recent content by ChowPuppy

Woke up today. Moved to the left, moved to the right. Nothing changed, it's just a-Noether day.

Homework Statement We have an infinitely long half-cylindrical shell of radius r and charge density σ as shown below I am supposed to find the electric field at a point on the cylindrical axis, as seen in the diagram. Consider a coordinate system where the cylinder extends infinitely along...

Hey tiny-tim, Thanks so much for the help! I was finally able to get it, I think you meant cosPXO instead of cosOPX possibly, but basically I was able to write PX*cosPXO = r - bcos\phi where \phi is the usual spherical coordinate phi, and then using the pythagorean theorem I rewrote PX and...

Homework Statement Consider the electric field of two protons b meters apart. The potential energy of the system is equal to: U = \frac{\epsilon_0}{2}\int {\bf E}^2dv = \int({\bf E}_1+ {\bf E}_2)^2dv = \frac{\epsilon_0}{2}\int {\bf E}_1^2dv + \frac{\epsilon_0}{2}\int {\bf E}_2^2dv +...

You don't need to decompose that with partial fractions. Split up the (u+1)/(u^2+1) as u/(u^2 + 1) + 1/(u^2+1). Now you can do a substitution on the 1st term and the 2nd term is just arctan(u). I'm not even sure that you could do a partial fraction decomposition on that because you can't factor...

You could do this just by plugging in numbers like sooo, although this isn't very elegant: cos(1)/(3/2) = 0.3602 cos(2)/(9/4) = -0.18495 cos(5)/(3/2)^5 = 0.03735 cos(10)/(3/2)^10 = -0.0145 cos(20)/(3/2)^20 = 0.000122 Were getting close.. cos(21)/(3/2)^21 = -0.0001098 cos(22)/(3/2)^22 =...

If so, could it be used to integrate sin(x)/ln(x)

Are the amplitudes of the electric and magnetic components of an electromagnetic wave proportional? Or is the amplitude of the electric portion unrelated to that of the magnetic portion?

I had this problem for my physics class where we had a 20eV photon interaction with hydrogen gas. It takes 13.6eV to knock electrons off of the atoms from the ground state after the photon is absorbed by the hydrogen atom, but that leaves 6.4eV left over. Does all of this energy go into the...