Recent content by Cilabitaon

I would, but the point is I have to use the chain rule as many times as I can. The points scored in the exercise are 5 for a correct answer and 2 for either the use of implicit differentiation or the chain rule. This is basic, I know, but we fail if we get less than 16 points.

Homework Statement A ladder, of length 13m, is leaning against a wall. The base of the ladder begins to slide, frictionless, away from the wall; by the time the base is horizontally 12m away from the wall it is moving at a rate of 2ms-1 a)How fast is the top of the ladder sliding down the...

I haven't done this in a while, but shouldn't the evaluation of (x+1) be x=-16, since there is a remainder of -15 when the polynomial is divided by (x+1)

I don't think there's any big deal about how the objects are connected, it's a simple problem. I do have a problem with your diagram, however; to me it seems that m_1 is attached directly to the massless string, whereas m_2 is not even connected to the string, only to the pulley(in turn -...

If you draw yourself a circle and arbitrarily mark the charge on the spheres surface (+ve since the charge is 3uC). Now you know the concept of an electric field line: it must follow the path a +ve charge would; with this you can see that there is no way to move a field line from the outside of...

It seems rational: as the units you would be given are Jm^{-2} which would imply the energy per unit area.

My point was that you may not always get away with just 'skipping' steps/information. Even if you did do the steps mentally, you should really change your intercept value to d or just something other than C

Which is correct, apart from the units; the units of resistance are Ohms, \Omega.

well, using Coulomb's Force(like you did), you get the equation F=\frac{1}{4 \pi \epsilon_{0}} \cdot \frac{Q_{U}Q_{e^{-}}}{r^{2}} Which then, by substitution: F=\frac{1}{4 \pi \times 8.85 \times 10^{-12}} \cdot \frac{(92 \times 1.6 \times 10^{-19}) \cdot (-1.6 \times 10^{-19})}{(0.1 \times...

Would you mind showing your working?

Surely the first two equations are wrong? If you take ln(u+1)=x+C then using exponents would transform these to e^{ln(u+1)}=e^{x+C} which then cancels to u+1=e^{x} \cdot e^{C} Usually in differential equations you take e^{C} to be a constant A So we end with the final equation...

I hope this has solved your problems.=]

That isn't what he meant: he was writing out the equation and it started on a new line. What he meant was: \frac{dy}{dx} = \frac{y'}{x'} = y' \cdot (x')^{-1} and if you ask me you needn't do that step and head straight on to the quotient rule: \frac{vdu - udv}{v^{2}} or...

Then there's your answer!

Just for future reference; any point along the circumference of a circle that creates a tangent to the circle will: a)be a distance r(radius) from the origin; b)form a right-angled triangle along the diameter of the circle with any other point on the circumference.