When Can We Find the Inverse of a Function Composition?

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Homework Help Overview

The discussion revolves around the conditions necessary for the existence of the inverse of a function composition, specifically focusing on the function g^(-1)f. Participants are exploring the relationships between the domains and ranges of the functions involved.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the logic behind the conditions for the existence of g^(-1)f, particularly whether the range of f must be a subset of the domain of g, similar to the condition for gf. There is also inquiry into the nature of relationships that qualify as functions.

Discussion Status

Some participants have provided insights regarding the types of relationships that are considered functions, noting the distinctions between one-to-one and many-to-one relationships. However, there is still exploration regarding the implications of these relationships on the composition fg^(-1).

Contextual Notes

Participants are discussing the definitions and properties of functions and their inverses, indicating a need for clarity on these foundational concepts. There is a repeated emphasis on the conditions required for function compositions to be valid.

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Homework Statement



What is the condition for the function g^(-1)f to exist ?

Homework Equations





The Attempt at a Solution



i know for function gf to exist , the range of f must be a subset or equal to the domain of g . Does it also work for g^(-1)f ? what is the logic behind that ?
 
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thereddevils said:

Homework Statement



What is the condition for the function g^(-1)f to exist ?

Homework Equations





The Attempt at a Solution



i know for function gf to exist , the range of f must be a subset or equal to the domain of g . Does it also work for g^(-1)f ? what is the logic behind that ?

Do you know which types of relationships are considered functions?
 


Cilabitaon said:
Do you know which types of relationships are considered functions?

yes , one to one relationships or many to one for functions and one to one only for inverse function
 


thereddevils said:
yes , one to one relationships or many to one for functions and one to one only for inverse function

Then there's your answer!
 


Cilabitaon said:
Then there's your answer!

thanks ! How is it different when its fg^(-1) ?
 

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