Recent content by Coderhk

Could I please get a hint on how I should start this question/how I should parameterize these variables? I'm going to head to sleep as I am from the eastern time zone. I apologize ahead of time for my delayed reply.

I believe the question is talking about a shpherical shell like a gaussian enclosed sphere. I figured out that I need to express h in terms of the cos law. Thanks.

Homework Statement Find the electric field of a point outside sphere without using Gauss's law. (Do not evaluate the integral) Homework Equations Coulomb's Law Spherical Co-ordinate System The Attempt at a Solution I have attached my attempt as a picture but now I am stuck, I don't know how I...

should the free body diagram look like this instead?

Shouldn't it be Nsin(beta-alpha)? I got to that answer based on my right most diagram. If the normal force was to be perpendicular to the surface it would be parallel to the bar right?

Homework Statement Part a of the image below. When I try to solve this question, I can't get the solution in the answer key. In the answer key the y component of the normal force is NCos(alpha) in the last line. Does the normal force not point perpendicular to the ramp? Homework Equations...

I tried using (H(x-a)-H(x-b))+H(b-x)-H(x-a)) Though that doesn't work. I've been stuck for a while. Could you please give me a hint?

I'm have already tried but can't seem to think of what to write. I know I can use H(x-a)-H(x-b) for a<x<=b but this excludes b

if x = b at H(b-x) it will be on at the value x <= b. Though I need a<=x<=b.

By using H(b-x) instead of H(x-b) we would make the function defined on the left endpoint value but that leaves the right endpoint undefined

Homework Statement Use the Heaviside function as an on the switch over the interval [a,b]. Homework Equations Let the H(x) be the Heaviside function defined as a piece-wise function such that it is zero if x is less than zero, and 1 if it is greater than or equal zero. From that, we can use the...

I attached the diagram

The possible choices are 4.4, 5.7, 10.4, 10.6,25.6

I Get it now thank you. I wasn't sure if I could make the assumption that the deepest part of the bowl is directly below the midpoint. But I see now. So the answer is 10.6

I I meant hemisphere