Recent content by conov3

Homework Statement A coil of wire has 600 turns and is 5.5 cm in diameter is in a magnetic field that decreases from 2.2 T to 0 T in 6.2 ms. The axis of the coil is parallel to the field. The coil is hooked up to two resistors of 120 Ω and 200 Ω connected in parallel. What is the maximum...

Yes, I just tried that.. and it didn't say it was correct. It usually will give me the answer if it is that close but it says that is the wrong answer.

1. Homework Statement At what distance (in m) from a very thin, straight wire carrying a 38 A current would the magnetic field strength be the same as a refrigerator magnet of 4.35 x 10-3 T? 2. Homework Equations B=(μo/2pi)*(I/d) where μo=4pi*10^-7 3. The Attempt at a Solution...

Homework Statement A hollow copper wire with an inner diameter of 1.4 mm and an outer diameter of 2.6 mm carries a current of 2.50 amps. Copper has an electron density of 8.5x1028 m-3 and a conductivity of 6.0x107 (ohm m)-1. a. What is the electron drift speed in the wire? b. What is the...

I appreciate the help! Thanks for your time :smile:

thank you! then for b, voltage drop=.32(14) and c, P=.322(12)=1.2288J?

So does that mean the second battery actually decreases the voltage at 8V? or do the lines within the battery not switch to show direction? I=(V1-V2)/(R+R+R) so I=(24-8)/50=>8/25 or .32Amps Vdrop=(.32)(14)=4.48V then another 8V from other battery. So before the last two resistors, 11.52V...

Homework Statement If R3 = 14Ω: a. What is the current out of the 24 V battery? b. What is the voltage drop across the R3 resistor? c. What is the power dissipated by the 12 Ω resistor? Homework Equations I=V/R V=V(R3/Rtotal) P=I2R The Attempt at a Solution Answers...

Homework Statement Two conducting spheres are connected by a thin wire and are in electrostatic equilibrium. The diameter of the smaller sphere is 2.0 cm and the diameter of the larger one is 9.0 cm. If the smaller sphere is found to be charged to 3.0 nC, what is the charge of the larger...

Thank you so much for the clarification!

So does that mean voltage drop =9*(27/33) => 7.36V?

Would I be able to break it up to 4.5V going both ways.. say V=IR I=4.5V/6ohms to get .75A That is where I get confused with how to find the voltage drop with more than one resistor

Series and parallel circuit with multiple resistors?? Homework Statement If R1 = 27Ω and R2 = 7Ω : a. What is the equivalent resistance of the circuit? b. What is the current from the battery? c. What is the voltage drop across the R1 resistor? Homework Equations I=V/R ΔV=-IR...

Homework Statement An electric dipole consists of 2.0 g spheres charged to 5.0 nC (positive and negative) at the ends of a 12 cm long massless rod. The dipole rotates on a frictionless pivot at its center. The dipole is held perpendicular to a uniform electric field with field strength...

Thanks a ton gneill! Better than a full class of learning haha :)