In the discussion, participants analyze the electrostatic equilibrium of two conducting spheres connected by a thin wire. The smaller sphere, with a diameter of 2.0 cm, carries a charge of 3.0 nC. The larger sphere, with a diameter of 9.0 cm, is determined to have a charge of 13.5 nC based on the ratio of their diameters. The formula for the potential at the surface of a charged conducting sphere is crucial for verifying the validity of this calculation.
PREREQUISITESStudents in physics, particularly those studying electrostatics, as well as educators and anyone interested in understanding charge distribution in conducting materials.
conov3 said:Homework Statement
Two conducting spheres are connected by a thin wire and are in electrostatic equilibrium. The diameter of the smaller sphere is 2.0 cm and the diameter of the larger one is 9.0 cm. If the smaller sphere is found to be charged to 3.0 nC, what is the charge of the larger sphere?
Homework Equations
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The Attempt at a Solution
2/3=9/x
x=13.5nC? Am i able to use this rule to find the charge