What is the Charge of the Larger Sphere in Electrostatic Equilibrium?

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Homework Statement



Two conducting spheres are connected by a thin wire and are in electrostatic equilibrium. The diameter of the smaller sphere is 2.0 cm and the diameter of the larger one is 9.0 cm. If the smaller sphere is found to be charged to 3.0 nC, what is the charge of the larger sphere?

Homework Equations



?

The Attempt at a Solution



2/3=9/x
x=13.5nC? Am i able to use this rule to find the charge
 
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conov3 said:

Homework Statement



Two conducting spheres are connected by a thin wire and are in electrostatic equilibrium. The diameter of the smaller sphere is 2.0 cm and the diameter of the larger one is 9.0 cm. If the smaller sphere is found to be charged to 3.0 nC, what is the charge of the larger sphere?

Homework Equations



?

The Attempt at a Solution



2/3=9/x
x=13.5nC? Am i able to use this rule to find the charge

Your result is correct.

You should verify that your 'rule' is valid. What is the formula for the potential at the surface of a charged conducting sphere?