# Dipoles angular velocity when aligned with electric field?

## Homework Statement

An electric dipole consists of 2.0 g spheres charged to 5.0 nC (positive and negative) at the ends of a 12 cm long massless rod. The dipole rotates on a frictionless pivot at its center. The dipole is held perpendicular to a uniform electric field with field strength 1400V, then released. What is the dipole’s angular velocity at the instant it is aligned with the electric field?

F=mω^2r
F=qE

## The Attempt at a Solution

F=qE
F=(5*10^-9)(1400)
F=7*10^-6N

7*10^-6=mω^2r
ω=√(7*10^-6/(.004*.12))
ω=.121rev/s?

I'm just unsure if I did this correctly, I thought it seemed to easy that way.