Maximum current through resistor in a coil of wire with two resistors in parallel

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SUMMARY

The discussion focuses on calculating the maximum current through a 200 Ω resistor in a parallel configuration with a 120 Ω resistor, connected to a coil with 600 turns in a magnetic field that decreases from 2.2 T to 0 T over 6.2 ms. Using Faraday's Law of Induction, the induced voltage (V) can be calculated, which is essential for determining the current (I) through the 200 Ω resistor using Ohm's Law (I = V/R). The equivalent resistance for the parallel resistors is also calculated using the formula R = (1/R1 + 1/R2)^-1.

PREREQUISITES
  • Understanding of Faraday's Law of Induction
  • Knowledge of Ohm's Law (I = V/R)
  • Ability to calculate equivalent resistance in parallel circuits
  • Familiarity with basic electromagnetic concepts
NEXT STEPS
  • Learn how to apply Faraday's Law of Induction in practical scenarios
  • Study the calculation of induced EMF in coils
  • Explore advanced resistor network analysis techniques
  • Investigate the effects of changing magnetic fields on current induction
USEFUL FOR

This discussion is beneficial for physics students, electrical engineering students, and anyone interested in understanding electromagnetic induction and circuit analysis involving resistors in parallel.

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Homework Statement



A coil of wire has 600 turns and is 5.5 cm in diameter is in a magnetic field that decreases from 2.2 T to 0 T in 6.2 ms. The axis of the coil is parallel to the field. The coil is hooked up to two resistors of 120 Ω and 200 Ω connected in parallel. What is the maximum current through the 200 Ω resistor?

Homework Equations



B=uoNI/l
I=V/R
R= (1/R1+1/R2)-1
?

The Attempt at a Solution



I know I need to find voltage and then find current of just the 200 ohm resistor
 
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Hint: Look up Faraday's Law of Induction
 

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