Recent content by copresh1

there is no fan invovled here( sorry i shud have mentioned)the cleansing media is steam and directed directly from a steam manifold.how do i go ahead?

I am trying to do a project on electrical engineering which involves design of electrical circuitry for a soot blower arrangement.i am having problems in designing a motor( 3phase induction motor). i know how to calculate the rotor parameters,losses, efficiency,etc. i am told that i have to find...

sorry for the delay in responding the value i get for relative permeability is 238734.802 i will scan and attach the method that i have followed to solve the prob till now.

using f=BLI i found B=100T next i used S=L/mew0*crosssectional area of air gap(L=10mm,c/sarea airgap=piD=3.14*0.001) =2533029.59A/wb next using H=IN/L(I=100mA,N=50,L=15mm this assumed) =333.33A/m but when i go to find relative permeabilty i am getting a...

F=BLI where B is flux density,L is length of conductor, and I is the current in the conductor. magnetic field density=magnetic flux/c/s area magnetic flux=mmf/reluctance & reluctance=lenght of airgap/mew0 * c/s A

i am a bit confused as to where to start on this problem, any hint will be appreciated.(problem attached)

attached diagram

i have derived the desired result. the second part of the problem(see atached)i do not know where to start.

i have drawn the phasor diagram ( which i will upload later). from the phasor diagram i can say that iLsin thetha=iCsin thetha

it is a RC series connected in parallel with RL.

a zobel network consisting of a capacitor C and resistance Rc is connected in parallel to a speaker of inductance L and resistance Rl.show that frequency at resonance =1/2pi*Sq rt 1/LC(Rlsquare-L/C ÷ Rc square-L/C) i have begun by equating the reactive components of the branch currents...

i was solving a prob the foll prob on electrical resonance. a resistance is connected in series with an inductor which inturn is connected to 2 capacitors(capacitors are in parallel w.r.t each other, and one of them is trimming capacitor).the circuit is now connected to a relay whose...

advantages:the core can be magnetized further disadvantages:lowers the efectiveness by inc the reluctance

it flatens the curve ie its a straight line

flatens it out