Recent content by crono_

Okay, it's clicking. Making the graph helped a fair bit. Would you always recommend looking at a graph if you're stuck? Or do you find that to be too time consuming? Once I have f(x) = x2 - 1 graphed, would it make sense to put f(x) = 4 - x on the same graph? If they intersect with each...

I don't know... The answer is supposed to be (- infinity, -1] U [1,4], but I'm not making sense of that. Anything squared, positive or negative, will end up being positive. Meaning that -22 (from your example) will be positive and therefore part of the domain. But I'm not sure I even...

It's a habit. :P Okay... 4 - x \geq 0 4 \geq x x2 - 1 \geq 0 x2 \geq 1 x \geq \sqrt{1} or just 1 So, now... 1 \leq x \leq 4 D: [1,4] ?

Homework Statement Find the domain of the function. h(x) = \sqrt{4 - x} + \sqrt{x^2 - 1} Homework Equations a2 - b2 = (a - b) (a + b) I think that's all... The Attempt at a Solution For starters, I know we can't have a negative number in the radical. I looked at the 2nd radical first and...

Comforting. haha :P Well, thanks for the comments anyways. They're appreciated, and comical! :)

Okay, thanks. That kind of helps to clear things up. Though I'm going to have to adjust to using calculus lingo. :) The dependent & independent terms came from the textbook: A symbol that represents an arbitrary number in the domain of a function f is called an independent variable...

Calculus is quite new to me, so I think I'm starting from scratch and might be in over my head. Forgive my basic knowledge... When considering two variables, how does one know which one is the independent or dependent variable? For instance - The area A of a circle depends on the radius r...

Wait... vy / vx = tan 75 vy = tan 75 (vx) vy = 10.0765 m/s vfy = voy + at vfy - voy / a = t t = 1.0282 s y = 1/2 (vfy + voy) t y = 1/2 (10.0765 m/s + 0 m/s) 1.0282 s y = 5.18 m ----> 5.2 m with sig figs Hrm...interesting....

tan-1 = (vy / vx) = 75 degrees

Homework Statement Suppose the water at the top of Niagara Falls has a horizontal speed of 2.7 m/s just before it cascades over the edge of the falls. At what vertical distance below the edge does the velocity vector of the water point downward at a 75° angle below the horizontal? x...

Any thoughts?

Homework Statement The handle of a hydraulic jack is 15 cm long and is pivoted 2.5 cm from the input piston which has a radius of 0.60 cm. The output piston has a radius of 1.2 cm. What weight could be lifted by the jack if the person pushing on the handle is to exert no more than 110 N of...

Great! Thanks a bunch for your help! :)

Didn't know what you meant by the g's cancelling, but I went back a few steps and tried this...Please excuse pi appearing as an exponent, I have no idea why that happens. p(4/3 \pir3)g + p(L*w*h)g = mg p(4/3 \pir3) + p(L*w*h) = m 1025 kg/m3 (24.429 m3) + 1025 kg/m3 (34.398 m3) 1025...

Hmmm... The buoyant force equals the weight of the displaced fluid which is the sea water, not the air. So the equation should have been: FB = Wwater = mg = pVballoong = 1025 * 24.429 * 9.8 = 245389 N So, using that... F = mg m = F / g m = 245389.30 N + 345527.91...