Recent content by davev

  1. D

    What Is the Cell Potential When Pb Electrode Mass Changes?

    I figured it out, but I'm somewhat confused. lnQ = [1.3708/1] is the right way to approach this problem. However, why doesn't the cathode concentration change at all? Edit: Sorry, this is wrong. It's closer than I've come before to the actual answer, but it's wrong. I'm assuming the cathode...
  2. D

    What Is the Cell Potential When Pb Electrode Mass Changes?

    Okay — could you explain what I have to do more clearly, because I don't have any other ideas on how to approach this problem.
  3. D

    What Is the Cell Potential When Pb Electrode Mass Changes?

    Isn't that what I did? I used that as the end product in my ICE table. To find change (i.e., x), 1 - x = 0.66158. The value of x would be the final concentration of Ni2+.
  4. D

    What Is the Cell Potential When Pb Electrode Mass Changes?

    I'm confused, because I don't think I get the right answer by doing this: 137.08 g Pb * (1 mol Pb/207.2 g Pb) * (1 mol Pb2+/1 mol Pb) = 0.66158 moles of Pb2+. I'm assuming that is also 0.66158 M of Pb2+ as there is 1 L of solution for both anode and cathode. 1 - x = 0.66158 x = 0.33842; this...
  5. D

    What Is the Cell Potential When Pb Electrode Mass Changes?

    That the concentration of both anode and cathode is 1 M. How would I incorporate the change in mass of the cathode electrode though?
  6. D

    Titration of Sulfurous Acid: Calculating pH with Ka Values

    How do I solve this problem in a way that would make sense given what I know at an introductory college chemistry level? Sorry, I just don't understand how to incorporate multiple Ka values even with the equation listed.
  7. D

    What Is the Cell Potential When Pb Electrode Mass Changes?

    Homework Statement Consider the following half reactions at 298 K Ni2+ + 2 e- → Ni Eo = -0.231 V Pb2+ + 2 e- → Pb Eo = -0.133 V A galvanic cell based on these half reactions is set up under standard conditions where each solution is 1.00 L and each electrode weighs exactly 100.0 g. What will...
  8. D

    Titration of Sulfurous Acid: Calculating pH with Ka Values

    Homework Statement A 0.551 L solution of 1.37 M sulfurous acid (Ka1 = 1.5e-2 and Ka2 = 1.0e-7) is titrated with 1.65 M NaOH. What will the pH of the solution be when 0.7549 L of the NaOH has been added? The answer is 7.27. Homework Equations -log(H+)=pH pH = pKa + log(salt/acid) The Attempt...
  9. D

    Kinetics Question: Rate of Reaction at 0.503 M

    ICE as in initial concentration, change in concentration, and end concentration. How do you solve this problem?
  10. D

    Kinetics Question: Rate of Reaction at 0.503 M

    Oh, do I have to use an ICE table?
  11. D

    Kinetics Question: Rate of Reaction at 0.503 M

    Homework Statement Consider the following reaction at 282 K. 2 A + 2 B → C + D where rate = rate=k[A][B]2. An experiment was performed for a certain number of seconds where [A]0 = 0.000303 M and [B]0 = 1.63 M. A plot of ln[A] vs time had a slope of -7.27. What will the rate of this...
  12. D

    Cell Potential with Nernst Equation

    The answer I put in is what the system shows as the correct answer now that the homework has closed. I don't understand why it was marked incorrect, but I'll just have to email my professor.
  13. D

    Cell Potential with Nernst Equation

    Homework Statement Homework Equations Nernst Equation where Q = [product]/[reactants], R = 8.314, F = 96500 The Attempt at a Solution I got E° to be 0.012 V because E° of cathode - E° of anode. -0.131 - (-0.143) = 0.012. The balanced equation I got was: Pb2+ + Sn → Pb + Sn2+ For the values of...
  14. D

    Normal Force/Scale: Clarifying Confused Concept

    I just wanted to clarify a concept that I'm confused about. When a problem states that a scale reads a value, is that value the normal force? If it is, is that value the normal force, let's say, on an accelerating elevator too? Or is it actually the weight on the accelerating elevator?