Cell Potential with Nernst Equation

[davev]

Homework Statement

Homework Equations

Nernst Equation where Q = [product]/[reactants], R = 8.314, F = 96500

The Attempt at a Solution

I got E° to be 0.012 V because E° of cathode - E° of anode. -0.131 - (-0.143) = 0.012.

The balanced equation I got was: Pb²⁺ + Sn → Pb + Sn²⁺

For the values of Q, I added 0.349 M to the concentration of Sn²⁺ as it's the product, and I subtracted 0.349 M from the concentration of Pb²⁺ as it's the reactant.

Plugging everything into the equation:
E = 0.012 V - ((8.314 * 271)/(2 * 96500)) * ln(1.318/0.576) = 0.0023 V. This answer is wrong, but I cannot figure out what I'm doing wrong here. Please help!

 

[Borek]

I can't find anything wrong.

Not that I am infallible, but there are two of us stumped now.

 

[davev]

The answer I put in is what the system shows as the correct answer now that the homework has closed. I don't understand why it was marked incorrect, but I'll just have to email my professor.