Recent content by davidhansson

oops, it's actually 6,67 as the book says,, it was just a computational mistake by me. thank you anyways guys! thanks/ David

So, the exercise is to find the expected value of following distribution: f(x) = 0,02x 0<x<10 answer in the book says 6,67 As far as I knowe, the expected value is calculated by the Integral of x * f(x) between 0 and 10, in this case! It looks like this won't give the result 6,67! what am...

Neither do I.. Ok, I think it was the M/A part I forgot,, I think I got it now,, thanks!

ok, I don't knowe if I'm making the integration in the right way. But I get W0*(L^2)/3 dM=(W0*(x^2)/L)dx Integration gives: M=W0*(x^3/3L) --> Inserting L and dividing with W0: (L^3/3L) --> L^2/3

Ok, thanks for help! I found something that were wrong in the calculation,, the integral should equal a*b/4 (area/2), because I'm looking for a x value that gives half of the area, which I call p! but the answer is still b/√2 otherwise, is there something incorrect with the integral? I also...

Hello,, I'm reading about beams in mechanics of matrials. But I'm a bit stuck because of one thing that I either don't understand or just don't comply with! So, here's a picture from the book: picture 003 It says that the center of mass should be at 2/3 of the length.. I tried to...

Hello, lots of thanks for the reply! What you're saying sounds fully logic and was also my intuition. The weird thing though is that they make one additional integration to the (1/2)*(25 x^2) kNm ,, so we get (1/6)*(25 x^3) kNm (from 0 to 0.6).. and then multiply with the constants ofc...

Hello, I'm studying machanics of materials.. I'm at the chapter that handles the angle of twist in shafts. There's one exercise that I get the most part of, but there's just a tiny part of it that I don't get! here's the exercise...