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Statistics: mean/expected value of an continuous distribution

  1. Sep 22, 2014 #1
    So, the exercise is to find the expected value of following distribution: f(x) = 0,02x 0<x<10

    answer in the book says 6,67

    As far as I knowe, the expected value is calculated by the Integral of x * f(x) between 0 and 10, in this case!
    It looks like this won't give the result 6,67!

    what am I doing wrong?

    thanks/ David
     
  2. jcsd
  3. Sep 22, 2014 #2

    statdad

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    I'm not sure. The expected value is this integral:
    [tex]
    E(X) = \int_0^{10} x f(x) \, dx
    [/tex]

    What do you get when you evaulate it?
     
  4. Sep 22, 2014 #3

    Ray Vickson

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    We cannot possibly help if you don't show us what you did in detail.
     
  5. Sep 22, 2014 #4
    oops, it's actually 6,67 as the book says,, it was just a computational mistake by me.

    thank you anyways guys!

    thanks/ David
     
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