Recent content by deepalakshmi

well, all the other elements are transition elements where as Mg is not.

I have seen the structures like X3 (HITP)2 (X = Cr, Mn, Fe, Co, Rh, Os, Ir). Can I replace X with Mg? Will it be stable?

From this graph what observations can be made?

This is graph which I got while plotting fidelity vs time. According to my graph, fidelity decreases and reaches 0 but again increases and decreases.

I read in an article that "Quantum physics is a highly mathematical theory that describes the nature of reality at the atomic and subatomic level". I also read another article that says quantum physics does not tell anything about reality. Can you give me some context about it in a way that is...

I was working on plotting fidelity with time for two quantum states. First I used discrete time( t= 0,1,2,3...etc) to plot my fidelity. I got constant fidelity as 1 with continuous value of time. Next I used discrete set of values ( t=0 °,30 °,60 °,90 °). Here I saw my fidelity decreases and...

While increasing the degree( 0,30,60,etc) fidelity keeps on decreasing and reaches 0 (1,0.2,0,0,0...). So can I conclude that overlapping of the two quantum state decreases while increasing the degree(time)?

$$F=|(\langle\alpha|\frac{\alpha\sqrt{3}}{2}\rangle)(\langle0|\frac{i\alpha}{2}\rangle)|^2$$ simplifying$$\langle\alpha|\frac{\sqrt{3}}{2}\alpha\rangle$$ $$=e^{-\frac{|\alpha|^2}{2}}\sum_{n=0}\frac{(\alpha^\ast)^n}{\sqrt{n!}}\langle...

Then how should I find inner product of the state with value inside it?

Since C is just a value, can't I take it outside?

@Demystifier Now considering t = 30(degree) $$|\psi\rangle=|\alpha\rangle|0\rangle$$ $$|\phi\rangle= |\cos(t)\alpha\rangle|i\alpha\sin(t)\rangle$$ $$= |(\sqrt{3}{/2})\alpha\rangle|(1{/2})i\alpha\rangle$$ $$F=|\sqrt{3}{/4}(|\langle\alpha|\langle...

But if take smaller values of alpha, I am not getting this statement. Why? For example; take alpha= sqrt{1}. Its inner product is 0.36 and fidelity is 0.1

At t=90(degree) its inner product is approximately equal to 0. Therefore its fidelity is 0 (approximately). Is this statement correct?

@Demystifier I am wrong. What my teacher meant was "At t = 90(degree), the fidelity is 0.00004 which is nearly equal to 0. But fidelity will be 0 only if the two states are orthogonal. But my case is not orthogonal. So he told me my calculation is wrong". I think it makes sense right? Therefore...

Is there something wrong with my initial and final state? "The fidelity between two states can be shown to never decrease when a non-selective quantum operation is applied to the states" what does this mean and how is it related to my problem?