Recent content by dipset24

Looking to find out how to integrate the following two: z=(A\partialu/\partialz)^(1/3) & z=(A\partialu/\partialz)^(n) Don't need the solution just need a reference or explicit statement of the integration rule.

Homework Statement Prove that the amplitude I_{0} of the steady periodic solution is maximal at w =1/\sqrt{LC}Homework Equations LI''+RI'+(1/C)*I=wE_{0}cos(wt) I(steady periodic)=E_{0}cos(wt-\alpha))/(\sqrt{R^2+(wL-(1/wC))^2}[b]3. The Attempt at a Solution [/b I can see by the graph that it...

Yes thank you so the Domain is [0,500] and when t=146.446609 min our concentration is 2lbs/gal

Yea i am sorry t=146.44 t= 853.553 However doesn't t have to be less then 500 going all the way back to the integrating factor. e^(-3*ln(500-t)) t<500?

Yes but when I plug that into my X(t)/v(t) (-4(t-500)+.000016(t-500)^3)/((500-t)=2 which I can reduce to 4-.000016(t-500)^2=2 but the answer t=853.55 is not correct I just need some help verifying my answer

Yes that is where I am caught up I tried several ways to get c and then plug it into x(t)/(500-t)=2lbs/gallonThe c I come up with is .000016

The initial conditions are x(0)=0 since it is all pure water at time 0 After solving using the integrating factor my x(t)(pounds of salt)= -4(t-500)+c(t-500)^3

Integrating Factor e^\int(3/(500-t)) dt = (500-t)^(-3) Dt\int [(500-t)^(-3)*x]dt=8\int(500-t)^(-3) (500-t)^(-3) X=4/(t-500)^2 + C

x'+(3/(500-t))x=8 was the DE I used

Homework Statement A 500 gallon tank is filled with pure water. A solution containing 4lbs of salt per gallon is added at a rate of 2 gallons per minute. The well-mixed solution is drained at a rate of 3 gallons per minute. A) How long does it take for the container to achieve a...

Homework Statement Most grandfather clocks have pendulums with adjustable lengths. One such clock loses 10 min per day when the length of its pendulum is 30in. With what length pendulum will this clock keep perfect time. Homework Equations none The Attempt at a Solution I don't...

Homework Statement Assume that the differential equation of a simple pendulum of length L is L\Theta'' + g\Theta=0 where g=GM/R^2 is the gravitational acceleration at the location of the pendulum. Two pendulums are of lengths L1 and L2 and when located at the respective distances R1 and...