- #1

- 12

- 0

z=(A[itex]\partial[/itex]u/[itex]\partial[/itex]z)^(1/3)

&

z=(A[itex]\partial[/itex]u/[itex]\partial[/itex]z)^(n)

Don't need the solution just need a reference or explicit statement of the integration rule.

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- Thread starter dipset24
- Start date

- #1

- 12

- 0

z=(A[itex]\partial[/itex]u/[itex]\partial[/itex]z)^(1/3)

&

z=(A[itex]\partial[/itex]u/[itex]\partial[/itex]z)^(n)

Don't need the solution just need a reference or explicit statement of the integration rule.

- #2

- 9,559

- 770

Looking to find out how to integrate the following two:

z=(A[itex]\partial[/itex]u/[itex]\partial[/itex]z)^(1/3)

Don't need the solution just need a reference or explicit statement of the integration rule.

Cube both sides and integrate it. Is u a function of variables other than z?

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