Mechanical Vibrations (Pendulums)

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SUMMARY

The discussion centers on the mathematical analysis of the period of simple pendulums using the differential equation LΘ'' + gΘ = 0, where g is defined as GM/R². The relationship between the periods of two pendulums of lengths L1 and L2, located at distances R1 and R2 from the Earth's center, is established as p1/p2 = R1√L1 / R2√L2. Participants emphasize the importance of understanding angular frequency (ω) and its relation to the period (T) in simple harmonic motion (SHM).

PREREQUISITES
  • Understanding of differential equations, specifically LΘ'' + gΘ = 0
  • Knowledge of gravitational acceleration defined as g = GM/R²
  • Familiarity with simple harmonic motion (SHM) concepts
  • Basic understanding of angular frequency (ω) and its relation to period (T)
NEXT STEPS
  • Study the derivation of the period of a simple pendulum using differential equations
  • Explore the concept of angular frequency in greater detail
  • Investigate the effects of varying lengths and gravitational fields on pendulum motion
  • Learn about the applications of simple harmonic motion in real-world systems
USEFUL FOR

Students in physics, educators teaching mechanics, and anyone interested in the dynamics of pendulum motion and simple harmonic systems.

dipset24
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Homework Statement



Assume that the differential equation of a simple pendulum of length L is L\Theta'' + g\Theta=0 where g=GM/R^2 is the gravitational acceleration at the location of the pendulum.

Two pendulums are of lengths L1 and L2 and when located at the respective distances R1 and R2 from the center of the earth-have periods p1 and p2. Show that:

p1/p2=R1\sqrt{L1}/R2\sqrt{L2}



The Attempt at a Solution


I do not know where to begin. If someone could help me out.
 
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Do you remember what the period, T, is equal to in SHM?
EDIT: Ah, ninja'd. :P
 

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