# Mechanical Vibrations (Pendulums)

1. Jun 21, 2009

### dipset24

1. The problem statement, all variables and given/known data

Assume that the differential equation of a simple pendulum of length L is L$$\Theta$$'' + g$$\Theta$$=0 where g=GM/R$$^2$$ is the gravitational acceleration at the location of the pendulum.

Two pendulums are of lengths L1 and L2 and when located at the respective distances R1 and R2 from the center of the earth-have periods p1 and p2. Show that:

p1/p2=R1$$\sqrt{L1}$$/R2$$\sqrt{L2}$$

3. The attempt at a solution
I do not know where to begin. If someone could help me out.

2. Jun 21, 2009

### Astronuc

Staff Emeritus
3. Jun 21, 2009

### RoyalCat

Do you remember what the period, T, is equal to in SHM?
EDIT: Ah, ninja'd. :P