Recent content by drag12

Your formula is correct, the difference is that you are assuming that the person invests $10,000 plus an additional $100 on day one. The formula that excel uses is starting the yearly $100 investments at the end of the first year.

Fairly recently someone started a topic here regarding the conjecture of Erdos about arithmetic progressions, namely that if A is a subset of the natural numbers and the sum of the reciprocals of elements of A diverges, then A contains arbitrarily long arithmetic progressions. I'm looking for...

If you're starting with something like (a+b)^{c+d} just break it into (a+b)^{c}(a+b)^{d} and use the usual http://en.wikipedia.org/wiki/Binomial_theorem for each part of the product, then multiply them together.

This is definitely not true of all Canadian universities. I am in an undergraduate math program at a mid sized Canadian university and I've never had to take an english class. I needed two semesters of any humanities class but that's the closest I've had to having to take english.

Master's programs in Canada are funded, and you don't need to know another language.

I'm not sure how you counted 12, but notice that each course that has a "Y" in the code is actually a two-semester course. First year students have at least two math courses each semester.

Degrees 2,4,6 etc are not shown on the graph because the Taylor expansion for sinx doesn't include those terms. sinx=x - (x^3)/3! + (x^5)/5! - (x^7)/7! + ... Yes you are correct that when they show degree 3 on the graph it includes the lower degree terms as well. Now about the power series...

I think you've just made a calculation error while checking your work. I just did the multiplication and (A+4I)x=0. Somehow when you multiplied the matrix by x you came up with just the negative of the third column in (A+4I). Try it again and if you're still having the same problem try googling...

A problem I'm having with your proof is where you say that d(x,a2)<r1 implies x is in B1, doesn't it just imply that it is in some ball B(a2,r1), not B1? Maybe I'm missing something but it seems like something isn't correct here, can you explain? Edit: Oh, looks like he deleted his post before...

Homework Statement Let (X,d) be a metric space. Suppose that a1,a2 in X and r1,r2>0 are such that the open ball B1(a1,r1) is a proper subset of the open ball B2(a2,r2). a) Prove that r1<r2. b)Must it always be true that r1< (3/2)*r2? Homework Equations The Attempt at a Solution...

I think the notation is just fooling you, x^0.5 is the same as sqrt(x), so your problem is: sqrt(x)=-1 Does that help?