Recent content by dykuma
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Undergrad Fabry-Perot Interferometer mirrors
I want to try to do spectroscopy of TLE's (sprites and things like that). They are quick and very faint, so using a regular narrowband filter might make them too hard to see. I was inspired by how solar telescopes use F-P's to observe fainter solar flares, and figured something similar was... -
Undergrad Fabry-Perot Interferometer mirrors
Thanks for the response, I appreciate it. Also sorry for taking so long to respond, I've been busy. Right, so the mirror I used wasn’t intended to be the final one. Mostly I was interested in seeing if it was possible at all to get fringes before I either attempted to make my own mirror or... -
Undergrad Fabry-Perot Interferometer mirrors
I am trying to build a Fabry-Perot interferometer to make some narrow band filters, and I was wondering if anyone can go into the specifics of whether there's anything special about the types of mirrors used in construction. I started by trying to see how hard it really is to make one on my... -
Graduate A mathematical description of the physics behind Aurora?
I should have clarified, I was asking about the colors/wavelengths of light of excited gasses (N2 and O2) as a function of altitude. Lightning at lower altitudes is blue, where light from excited nitrogen is dominate, and I was considering the excitation due to lower and upper atmospheric...- dykuma
- Post #3
- Forum: Beyond the Standard Models
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Graduate A mathematical description of the physics behind Aurora?
Maybe a bit of an odd question (not really sure where it would belong on this site to be honest), but I was wondering if anyone can explain, or at least knows of a source that explains in a quantitative way, the physics behind aurora? Now I've seen websites like this that discuss conceptually...- dykuma
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- Aurora Emission Fluorescence Lightning Mathematical Physics
- Replies: 3
- Forum: Beyond the Standard Models
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Force density from an electromagnetic field
Actually, I see that I made an error there. I'm not sure this makes sense though. I would expect there to be some mechanical work done (because the energy per volume is not zero), but because of the dot product (I'm dotting everything that's in the ##\hat x## direction with the current density...- dykuma
- Post #12
- Forum: Advanced Physics Homework Help
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Force density from an electromagnetic field
To go through all of this then, does this look correct to you?- dykuma
- Post #11
- Forum: Advanced Physics Homework Help
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Force density from an electromagnetic field
Right, so because: $$ \vec J = \rho \vec v$$ So I want: $$ P_V = \vec F \cdot \frac {\vec J} {\rho}$$ ?- dykuma
- Post #9
- Forum: Advanced Physics Homework Help
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Force density from an electromagnetic field
So then, what did I do wrong here?- dykuma
- Post #6
- Forum: Advanced Physics Homework Help
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Force density from an electromagnetic field
That's what I thought. However, when I tried to simplify it, I got: $$\nabla \times (\vec B \times \vec B) = \vec B(\nabla \cdot \vec B) - \vec B(\nabla \cdot \vec B) + (\nabla \cdot \vec B)\vec B - (\nabla \cdot \vec B)\vec B = 0$$ But when I actually carried out the work, I got an answer. I...- dykuma
- Post #4
- Forum: Advanced Physics Homework Help
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Force density from an electromagnetic field
Nevermind, I figured it out. The problem was that I took the cross product incorrectly. it should have been: $$(\nabla \times \vec B) \times \vec B$$ not $$\nabla \times (\vec B \times \vec B)$$- dykuma
- Post #2
- Forum: Advanced Physics Homework Help
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Force density from an electromagnetic field
My guess is that the force per volume is: $$ \vec F_V = \rho \alpha x \hat x + \vec J \times \beta x \hat y$$ but I'm not sure where to go after that. I'm not given a value for either the charge density or the current density, so I can't simplify the relation much. Further, I'm not sure if my...- dykuma
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- Density Electromagnetic Electromagnetic field Field Force
- Replies: 13
- Forum: Advanced Physics Homework Help
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Hermitian Matrix and Commutation relations
I think I roughly see what's happening here. > First, I will assume that AB - BA = C, without the complex number. >Matrix AB equals the transpose of BA. (AB = (BA)t) >Because AB = (BA)t, or because of the cyclic property of matrix multiplication, the diagonals of AB equals the diagonals of...- dykuma
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- Commutation Hermitian Matrix Relations
- Replies: 2
- Forum: Calculus and Beyond Homework Help
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Evaluating an integral of an exponential function
I had thought about looking through his channel, but I was not sure what to look for on there. That's exactly what I needed though. Thanks!- dykuma
- Post #3
- Forum: Calculus and Beyond Homework Help
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Evaluating an integral of an exponential function
the integral is: and according to mathematica, it should evaluate to be: . So it looks like some sort of Gaussian integral, but I'm not sure how to get there. I tried turning the cos function into an exponential as well: however, I don't think this helps the issue much.- dykuma
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- Exponential Exponential function Function Integral
- Replies: 3
- Forum: Calculus and Beyond Homework Help