Recent content by emeraldempres

At time t1 = 0 an electric grinding wheel has an angular velocity of 28.0 rad/s. It has a constant angular acceleration of 32.0 rad/s2. At time t2 = 2.20 s a circuit breaker trips, and the wheel then turns through another 350 rad as it coasts to a stop at constant angular acceleration. (i)...

anything else that can hellp me?

A glider of mass 0.147 kg is moving to the right on a frictionless, horizontal air track with a speed of 0.720m/s . It has a head-on collision with a glider 0.309 kg that is moving to the left with a speed of 2.26 m/s. Suppose the collision is elastic. Find the magnitude of the final velocity of...

thanks. i went back through my math and found an error, the answer is -2.16 J

I just tried that one and my homework says that -2.76 and 2.76 are not right. Anything else i can do?

i think that the kinetic energy is what is not being conserved because it is being transferred to puck b. the initial ke of a is a: ke= .5(.5)(-3.5^2)= 3.0625 b: ke= .5 (.2)(2^2)= 1 and the final ke is ke= .5(.5+.2)(-1.93^2)= 1.304 I had all these and subtract them from eacj other...

The initial velocity i believe to be 0 m/s because the answer does not specify. using this, since the ke is equal to .5mv^2, the initial ke is 0 J. am i on the right track?

On a greasy, essentially frictionless lunch counter, a submarine sandwich of mass 0.500 kg, moving with speed 3.50 m/s to the left, collides with a grilled cheese sandwich of mass 0.200 kg moving with speed 2.00 m/s to the right. How much mechanical energy dissipates in the collision? I...

On a frictionless, horizontal air table, puck A (with mass 0.245 kg) is moving toward puck B (with mass 0.360 kg), that is initially at rest. After the collision, puck A has a velocity of 0.115 m/s to the left, and puck B has velocity 0.660 m/s to the right. Calculate the change in the total...

on part b i find the kinetic force to be 107.6 N and the kinetic energy to 26005.52 N. am i correct in thinking that the kinectic force is going to be energy that gets converted into thermal energy?

thank you. i got the answer this is what i did 36465.8=.5*61v^2+1.04*10^4 26065=.5*61*v^2 854.61=v^2 v=29.2

and i do not know how to calulate how much is left at the bottom

she lost -1.04*10^4 J to friction

her starting mechanical energy is 0 right?

in trying this, i tried to find the potential energy which i found to be 36465.8 N by using u= mgy (m=61 kg, g= 9.8 meters per second squared, y= 61 m). in doing that the only unknown i had was velocity and it came out to be 34.57 m/s and that was wrong.. did i mess up?