Recent content by Emethyst
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Finding point on paraboloid surface given normal line point
Many thanks for the help you guys, I know where I went wrong now, I messed up inputting the given point into the normal line equation it seems. Finally got the cubic function and an answer that makes sense. Really appreciated it :smile:- Emethyst
- Post #4
- Forum: Calculus and Beyond Homework Help
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Finding point on paraboloid surface given normal line point
Homework Statement [/B] Find the coordinates of the point P on the surface of the paraboloid z=6x2+6y2-(35/6) where the normal line to the surface passes through the point (25/6, (25√22)/6, -4). Note that a graphing calculator may be used to solve the resulting cubic equation. Homework...- Emethyst
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- Line Normal Normal line Paraboloid Point Surface
- Replies: 6
- Forum: Calculus and Beyond Homework Help
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Potential energy for a dipole between 2 infinitely large charged sheets
Homework Statement A dipole consisting of charges +/- e 220 nm apart is placed between two very large (essentially infinite) sheets carrying equal but opposite charge densities of 125 uC/m^2. a) What is the maximum potential energy this dipole can have due to the sheets, and how should it...- Emethyst
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- Charged Dipole Energy Potential Potential energy
- Replies: 1
- Forum: Introductory Physics Homework Help
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Hooke's Law derivation problem involving two blocks
Ok, so there is then going to be only one Fnet equation?- Emethyst
- Post #4
- Forum: Introductory Physics Homework Help
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Hooke's Law derivation problem involving two blocks
Homework Statement A block with mass M rests on a frictionless surface and is connected to a horizontal spring of force constant k, the other end of which is attached to a wall. A second block with mass m rests on top of the first block. The coefficient of static friction between the blocks is...- Emethyst
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- Blocks Derivation Hooke's law Law Two blocks
- Replies: 4
- Forum: Introductory Physics Homework Help
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Exercise Program Homework: Calculating Jumps & Time Needed
Ahh I thought I converted it wrong, thanks for pointing out my mistake, however, if I use the new value that gives me, I get an answer too large (2.85x10^4 when it should be 1.1x10^3); is there some other place I'm going wrong here?- Emethyst
- Post #3
- Forum: Introductory Physics Homework Help
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Exercise Program Homework: Calculating Jumps & Time Needed
Homework Statement A 75kg person is put on an exercise program by a physical therapist, the goal being to burn up to 500 food calories in each daily session. Human muscles are about 20% efficient in converting energy into mechanical energy. The exercise program consists of a set of consecutive...- Emethyst
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- Exercise Program
- Replies: 2
- Forum: Introductory Physics Homework Help
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Energy-related problem involving skiing up a hill
Homework Statement A 68kg skier approaches the foot of a hill with a speed of 15m/s. The surface of the hill slopes up at 40 degrees above the horizontal and has the coefficients of static and kinetic friction of 0.75 and 0.25, respectively. Use energy conservation to find the maximum height...- Emethyst
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- Hill Skiing
- Replies: 1
- Forum: Introductory Physics Homework Help
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Biting Force Distribution in Herbivorous and Carnivorous Jaws
I believe so, although it should not affect the answer though I do not think, since the question is not asking for an exact value. This is what is confusing me, I'm not sure how to relate the positions of the forces to the relative bite force created by the jaw.- Emethyst
- Post #6
- Forum: Introductory Physics Homework Help
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Biting Force Distribution in Herbivorous and Carnivorous Jaws
Ohh sorry for missing the picture, my apologies, here it is:- Emethyst
- Post #3
- Forum: Introductory Physics Homework Help
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Biting Force Distribution in Herbivorous and Carnivorous Jaws
Homework Statement In a typical herbivore, the max magnitude of the force T (temporalis muscle) is 1/10 the max magnitude of the force M (masseter and pterygoideus muscles). a) Assuming that there is a force at the joint, would it be expected that the animal would exert the largest biting...- Emethyst
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- Forces
- Replies: 5
- Forum: Introductory Physics Homework Help
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Downward-Facing Dog Equilibrium Question
Ahh I see now how to do part A. I'm still lost on part B however; how would I determine the force of friction on both the hands and feet? I know they will both act horizontally, but I'm not sure how to separate the upper and lower halves of the body to solve for either of them.- Emethyst
- Post #3
- Forum: Introductory Physics Homework Help
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Downward-Facing Dog Equilibrium Question
Homework Statement One yoga exercise, known as the downward-facing dog, requires stretching your hands straight out above your head and bending down to lean against the floor. This exercise is performed by a 750N person. When he bends his body at the hip to a 90 degree angle between his legs...- Emethyst
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- Equilibrium
- Replies: 2
- Forum: Introductory Physics Homework Help
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Calculating Acceleration on Ice: Max Possible for 60.9kg Person
Homework Statement A 60.9kg person wishes to run on ice. The coefficient of static friction between his shoes and the ice is 0.123. What is his maximum possible acceleration? Homework Equations Newton's laws of motion The Attempt at a Solution I figured that Fnet = Ffr, with me...- Emethyst
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- Acceleration Ice Max
- Replies: 1
- Forum: Introductory Physics Homework Help